∵ 6 students need = 3 computers ∴ 1 student needs = 3/6 = computers ∴ 24 students need = 3/6 x 24 = 12 computers Thus, 12 computers will be needed for 24 students. Class 7 Maths Chapter 8 Exercise 8.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-8/
∵ 6 students need = 3 computers
∴ 1 student needs = 3/6 = computers
∴ 24 students need = 3/6 x 24 = 12 computers
Thus, 12 computers will be needed for 24 students.
To find ratios, both quantities should be in same unit. (a) ₹5 to 50 paise ⇒ 5 x 100 paise to 50 paise [ ∵ ₹ 1 = 100 paise] ⇒ 500 paise to 50 paise Thus, the ratio is = 500/50 = 10/1 = 10:1 (b) 15 kg to 210 g ⇒ 15 x 1000 g to 210 g [ ∵ 1 kg = 1000 g] ⇒ 15000 g to 210 g Thus, the ratio is = 15000/210Read more
To find ratios, both quantities should be in same unit.
(a) ₹5 to 50 paise
⇒ 5 x 100 paise to 50 paise [ ∵ ₹ 1 = 100 paise]
⇒ 500 paise to 50 paise
Thus, the ratio is = 500/50 = 10/1 = 10:1
(b) 15 kg to 210 g
⇒ 15 x 1000 g to 210 g [ ∵ 1 kg = 1000 g]
⇒ 15000 g to 210 g
Thus, the ratio is = 15000/210 = 500 : 7
(c) 9 m to 27 cm
⇒ 9 x 100 cm to 27 cm [ 1 m = 100 cm]
⇒ 900 cm to 27 cm
Thus, the ratio is = 900/27 = 100/3 = 100 : 3
(d) 30 days to 36 hours
⇒ 30 x 24 hours to 36 hours [ ∵ 1 day = 24 hours]
⇒ 720 hours to 36 hours
Thus, the ratio is = 720/36 = 20/1 = 20 : 1
In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?
∵ 6 students need = 3 computers ∴ 1 student needs = 3/6 = computers ∴ 24 students need = 3/6 x 24 = 12 computers Thus, 12 computers will be needed for 24 students. Class 7 Maths Chapter 8 Exercise 8.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-8/
∵ 6 students need = 3 computers
∴ 1 student needs = 3/6 = computers
∴ 24 students need = 3/6 x 24 = 12 computers
Thus, 12 computers will be needed for 24 students.
Class 7 Maths Chapter 8 Exercise 8.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-8/
Find the ratio of: (a) ₹5 to 50 paise (b) 15 kg to 210 g (c) 9 m to 27 cm (d) 30 days to 36 hours
To find ratios, both quantities should be in same unit. (a) ₹5 to 50 paise ⇒ 5 x 100 paise to 50 paise [ ∵ ₹ 1 = 100 paise] ⇒ 500 paise to 50 paise Thus, the ratio is = 500/50 = 10/1 = 10:1 (b) 15 kg to 210 g ⇒ 15 x 1000 g to 210 g [ ∵ 1 kg = 1000 g] ⇒ 15000 g to 210 g Thus, the ratio is = 15000/210Read more
To find ratios, both quantities should be in same unit.
(a) ₹5 to 50 paise
⇒ 5 x 100 paise to 50 paise [ ∵ ₹ 1 = 100 paise]
⇒ 500 paise to 50 paise
Thus, the ratio is = 500/50 = 10/1 = 10:1
(b) 15 kg to 210 g
⇒ 15 x 1000 g to 210 g [ ∵ 1 kg = 1000 g]
⇒ 15000 g to 210 g
Thus, the ratio is = 15000/210 = 500 : 7
(c) 9 m to 27 cm
⇒ 9 x 100 cm to 27 cm [ 1 m = 100 cm]
⇒ 900 cm to 27 cm
Thus, the ratio is = 900/27 = 100/3 = 100 : 3
(d) 30 days to 36 hours
⇒ 30 x 24 hours to 36 hours [ ∵ 1 day = 24 hours]
⇒ 720 hours to 36 hours
Thus, the ratio is = 720/36 = 20/1 = 20 : 1
Class 7 Maths Chapter 8 Exercise 8.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-8/