Given A.P.: -11, -8, -5, ..., 49 Common difference d = -8 - (-11) = 3 Last term aₙ = 49 Using first term a₁ = -11 and d = 3, find n: aₙ = a₁ + (n-1)d 49 = -11 + (n-1)3 49 + 11 = 3(n-1) 60 = 3(n-1) 20 = n-1 n = 21 Therefore total terms = 21 4th term from end means: Position from beginning = n - 3 = 2Read more
Given A.P.: -11, -8, -5, …, 49
Common difference d = -8 – (-11) = 3
Last term aₙ = 49
Using first term a₁ = -11 and d = 3, find n:
aₙ = a₁ + (n-1)d
49 = -11 + (n-1)3
49 + 11 = 3(n-1)
60 = 3(n-1)
20 = n-1
n = 21
Therefore total terms = 21
4th term from end means:
Position from beginning = n – 3 = 21 – 3 = 18th term
Using arithmetic sequence formula:
a₁₈ = a₁ + (18-1)d
= -11 + (17)3
= -11 + 51
= 40
Hence, 40 is the correct answer.
The MCQs in Chapter 4 (Data Handling and Presentation) serve as crucial tools for assessing students' understanding of fundamental data concepts and their real-world applications. These questions help develop analytical thinking statistical literacy and visual interpretation skills through practicalRead more
The MCQs in Chapter 4 (Data Handling and Presentation) serve as crucial tools for assessing students’ understanding of fundamental data concepts and their real-world applications. These questions help develop analytical thinking statistical literacy and visual interpretation skills through practical scenarios. By testing knowledge of tally marks pictographs bar graphs mean median and mode the MCQs build strong problem-solving abilities. They enable students to make informed decisions based on data analysis and prepare them for advanced mathematical concepts in higher classes while ensuring effective application of theoretical knowledge in everyday situations.
The 4th term from the end of the A.P. -11, -8, -5, …, 49 is
Given A.P.: -11, -8, -5, ..., 49 Common difference d = -8 - (-11) = 3 Last term aₙ = 49 Using first term a₁ = -11 and d = 3, find n: aₙ = a₁ + (n-1)d 49 = -11 + (n-1)3 49 + 11 = 3(n-1) 60 = 3(n-1) 20 = n-1 n = 21 Therefore total terms = 21 4th term from end means: Position from beginning = n - 3 = 2Read more
Given A.P.: -11, -8, -5, …, 49
Common difference d = -8 – (-11) = 3
Last term aₙ = 49
Using first term a₁ = -11 and d = 3, find n:
aₙ = a₁ + (n-1)d
49 = -11 + (n-1)3
49 + 11 = 3(n-1)
60 = 3(n-1)
20 = n-1
n = 21
Therefore total terms = 21
4th term from end means:
Position from beginning = n – 3 = 21 – 3 = 18th term
Using arithmetic sequence formula:
a₁₈ = a₁ + (18-1)d
= -11 + (17)3
= -11 + 51
= 40
Hence, 40 is the correct answer.
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If 5 times the 5ᵗʰ term of an AP is equal to 8 times the 8ᵗʰ term then find its 13ᵗʰ term
Given: 5a₅ = 8a₈ where aₙ = a₁ + (n-1)d Let's substitute terms: 5[a₁ + 4d] = 8[a₁ + 7d] 5a₁ + 20d = 8a₁ + 56d 5a₁ - 8a₁ = 56d - 20d -3a₁ = 36d a₁ = -12d Now, for 13th term: a₁₃ = a₁ + 12d = -12d + 12d = 0 Thus, the 13th term of this AP is 0. Click here for more: https://www.tiwariacademy.in/ncert-soRead more
Given: 5a₅ = 8a₈
where aₙ = a₁ + (n-1)d
Let’s substitute terms:
5[a₁ + 4d] = 8[a₁ + 7d]
5a₁ + 20d = 8a₁ + 56d
5a₁ – 8a₁ = 56d – 20d
-3a₁ = 36d
a₁ = -12d
Now, for 13th term:
a₁₃ = a₁ + 12d
= -12d + 12d
= 0
Thus, the 13th term of this AP is 0.
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Class 6 Maths Ganita Prakash Chapter 4 MCQ?
The MCQs in Chapter 4 (Data Handling and Presentation) serve as crucial tools for assessing students' understanding of fundamental data concepts and their real-world applications. These questions help develop analytical thinking statistical literacy and visual interpretation skills through practicalRead more
The MCQs in Chapter 4 (Data Handling and Presentation) serve as crucial tools for assessing students’ understanding of fundamental data concepts and their real-world applications. These questions help develop analytical thinking statistical literacy and visual interpretation skills through practical scenarios. By testing knowledge of tally marks pictographs bar graphs mean median and mode the MCQs build strong problem-solving abilities. They enable students to make informed decisions based on data analysis and prepare them for advanced mathematical concepts in higher classes while ensuring effective application of theoretical knowledge in everyday situations.
Click here for more:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-6/