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  1. Asked: In:

    Factorize the expressions and divide them as directed: (i) (y²+7y+10) ÷ (y+5) (ii) (m² – 14m – 32) ÷ (m+2)

    Evaraj

    (i) (y²+7y+10) ÷ (y+5) = y²+7y+10/y+5 = y²+(2+5)y+2x5/(y+5) = y²+2y+5y+2x5/(y+5) = (y+2)(y+5)/(y+5) [∵ x²+(a+b)x+ab=(x+a)(x+b)] = y+2 (ii) (m² – 14m – 32) ÷ (m+2) = m² – 14m – 32/(m+2) = m²+(-16+2)m+(-16)x2/(m+2) = (m-16)(m+2)/(m+2) [∵ x²+(a+b)x+ab=(x+a)(x+b)] = (m + 2) Class 8 Maths Chapter 11 ExerRead more

    (i) (y²+7y+10) ÷ (y+5) = y²+7y+10/y+5
    = y²+(2+5)y+2×5/(y+5) = y²+2y+5y+2×5/(y+5)
    = (y+2)(y+5)/(y+5) [∵ x²+(a+b)x+ab=(x+a)(x+b)]
    = y+2

    (ii) (m² – 14m – 32) ÷ (m+2) = m² – 14m – 32/(m+2) = m²+(-16+2)m+(-16)x2/(m+2)
    = (m-16)(m+2)/(m+2) [∵ x²+(a+b)x+ab=(x+a)(x+b)]
    = (m + 2)

    Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

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  2. Asked: In:

    Divide as directed: (i) 5(2x+1)(3x+5) ÷ (2x+1) (ii) 26xy (x+5) (y-4) ÷13x (y-4)

    Evaraj

    (i) 5(2x+1)(3x+5) ÷ (2x+1) = 5(2x+1)(3x+5)/(2x+1) = 5(3x+5) (ii) 26xy (x+5) (y-4) ÷13x (y-4) = 26xy(x+5)(y-4)/13x(y-4) = 13X2Xxy(x+5)(y-4)/13x(y-4) = 2y(x+5) Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/mathsRead more

    (i) 5(2x+1)(3x+5) ÷ (2x+1) = 5(2x+1)(3x+5)/(2x+1)
    = 5(3x+5)

    (ii) 26xy (x+5) (y-4) ÷13x (y-4) = 26xy(x+5)(y-4)/13x(y-4)
    = 13X2Xxy(x+5)(y-4)/13x(y-4) = 2y(x+5)

    Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

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    • 5
  3. Asked: In:

    Work out the following divisions: (10x-25)÷5 (ii) (10x-25) ÷ (2x-5)

    Evaraj

    (i) (10x-25)÷5 = 10x-25/5 = 5(2x-5)/5 = 2x-5 (ii) (10x-25) ÷ (2x-5) = (10x-25)/2x-5 = 5(2x-5)/(2x-5) = 5 Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

    (i) (10x-25)÷5 = 10x-25/5 = 5(2x-5)/5 = 2x-5

    (ii) (10x-25) ÷ (2x-5) = (10x-25)/2x-5 = 5(2x-5)/(2x-5) = 5

    Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

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    • 5
  4. Asked: In:

    Divide the given polynomial by the given monomial: (i) (5x² – 6x)÷3x (ii) (3y⁸-4y⁶+5y⁴)÷y⁴

    Evaraj

    (i) (5x²– 6x)÷3x = 5x²-6x/3x = 5x²/3x - 6x/3x = 5/3 (x-2) = 1/3(5x-6) (ii) (3y⁸-4y⁶+5y⁴)÷y⁴ = 3y⁸-4y⁶+5y⁴/y⁴ = 3y⁸/y⁴ - 4y⁶/y⁴ + 5y⁴/y⁴ = 3y⁴ - 4y² + 5 Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chaptRead more

    (i) (5x²– 6x)÷3x = 5x²-6x/3x = 5x²/3x – 6x/3x = 5/3 (x-2) = 1/3(5x-6)
    (ii) (3y⁸-4y⁶+5y⁴)÷y⁴ = 3y⁸-4y⁶+5y⁴/y⁴ = 3y⁸/y⁴ – 4y⁶/y⁴ + 5y⁴/y⁴ = 3y⁴ – 4y² + 5

    Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

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    • 4
  6. Asked: In:

    Carry out the following divisions: (i) 28x² ÷ 56x (ii) -36y³ ÷ 9y²

    Evaraj

    (i) 28x⁴ ÷ 56x = 28x⁴/56x = 28/56 X x⁴/x = 1/2(x³) [∵ xᵐ ÷ xⁿ = xᵐ⁻ⁿ] (ii) -36y³ ÷ 9y² = 36y³/9y² = -36/9 X y³/y² = -4y [∵ xᵐ ÷ xⁿ = xᵐ⁻ⁿ] Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

    (i) 28x⁴ ÷ 56x = 28x⁴/56x = 28/56 X x⁴/x = 1/2(x³) [∵ xᵐ ÷ xⁿ = xᵐ⁻ⁿ]
    (ii) -36y³ ÷ 9y² = 36y³/9y² = -36/9 X y³/y² = -4y [∵ xᵐ ÷ xⁿ = xᵐ⁻ⁿ]

    Class 8 Maths Chapter 11 Exercise 14.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/

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    • 4