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Eesha

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  1. Asked: March 14, 2021In: Class 8 Maths

    Find the values of the letters in the following and give reasons for the steps involved.

    Best Answer
    Eesha
    Added an answer on March 14, 2021 at 12:25 pm

    Putting A = 8 and B = 1, we get 8 + 1 = 9 Now again we add 2 + 8 = 10 Tens place digit is ‘0’ and carry over 1. Now 1 + 6 + 1 = 8 = A Hence, A = 8 and B = 1 Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/Read more

    Putting A = 8 and B = 1, we get
    8 + 1 = 9
    Now again we add 2 + 8 = 10
    Tens place digit is ‘0’ and carry over 1.
    Now 1 + 6 + 1 = 8 = A
    Hence, A = 8 and B = 1

    Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

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  2. Asked: March 14, 2021In: Class 8 Maths

    Find the values of the letters in the following and give reasons for the steps involved.

    Best Answer
    Eesha
    Added an answer on March 14, 2021 at 12:24 pm

    On putting B = 7, ⇒ 7 + 1 = 8 Now A = 4, then 4 + 7 = 11 Putting 1 at tens place and carry over 1, we get 2 + 4 + 1 = 7 Hence, A = 4 and B = 7 Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

    On putting B = 7,
    ⇒ 7 + 1 = 8
    Now A = 4, then 4 + 7 = 11
    Putting 1 at tens place and carry over 1, we get
    2 + 4 + 1 = 7
    Hence, A = 4 and B = 7

    Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

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  3. Asked: March 14, 2021In: Class 8 Maths

    Find the values of the letters in the following and give reasons for the steps involved.

    Best Answer
    Eesha
    Added an answer on March 14, 2021 at 12:23 pm

    On putting B = 9, we get 9 + 1 = 10 Putting 0 at ones place and carry over 1, we get For A = 7 ⇒ 7 + 1 + 1 = 9 Hence, A = 7 and B = 9 Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

    On putting B = 9, we get 9 + 1 = 10
    Putting 0 at ones place and carry over 1, we get
    For A = 7 ⇒ 7 + 1 + 1 = 9
    Hence, A = 7 and B = 9

    Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

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    • 8
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  4. Asked: March 14, 2021In: Class 8 Maths

    Find the values of the letters in the following and give reasons for the steps involved.

    Best Answer
    Eesha
    Added an answer on March 14, 2021 at 12:21 pm

    Here product of B and 6 must be same as ones place digit as B. 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24 On putting B = 4, we get the ones digit 4 and remaining two B’s value should be 44. ⇒ For 6 x 7 = 42 + 2 = 44 Hence, A = 7 and B = 4 Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video fRead more

    Here product of B and 6 must be same as ones place digit as B.
    6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24
    On putting B = 4, we get the ones digit 4 and remaining two B’s value should be 44.
    ⇒ For 6 x 7 = 42 + 2 = 44
    Hence, A = 7 and B = 4

    Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

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  5. Asked: March 14, 2021In: Class 8 Maths

    Find the values of the letters in the following and give reasons for the steps involved.

    Best Answer
    Eesha
    Added an answer on March 14, 2021 at 12:20 pm

    Here on putting B = 0, we get 0 x 3 = 0. And A = 5, then 5 x 3 = 15 ⇒ A = 5 and C = 1 Hence, A = 5, B = 0 and C = 1 Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

    Here on putting B = 0, we get 0 x 3 = 0.
    And A = 5, then 5 x 3 = 15
    ⇒ A = 5 and C = 1
    Hence, A = 5, B = 0 and C = 1

    Class 8 Maths Chapter 11 Exercise 16.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/

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