According to Ohm’s law, V = IR ⟹𝑅=𝑉/𝐼 Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore, 𝑅=12/0.0025=4800 Ω=4.8 kΩ For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
According to Ohm’s law, V = IR
⟹𝑅=𝑉/𝐼
Here, V = 12 V and I = 2.5 mA = 0.0025 A
Therefore,
𝑅=12/0.0025=4800 Ω=4.8 kΩ
When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.
According to Ohm’s law, V = IR ⟹𝑅=𝑉/𝐼 Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore, 𝑅=12/0.0025=4800 Ω=4.8 kΩ For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
According to Ohm’s law, V = IR
⟹𝑅=𝑉/𝐼
Here, V = 12 V and I = 2.5 mA = 0.0025 A
Therefore,
𝑅=12/0.0025=4800 Ω=4.8 kΩ
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/