(i) 16² = 256 and 17² = 289 ⇒ 289 – 256 – 1 = 32 numbers. (ii) 99² = 9801 and 100² = 10000 ⇒ 10000 – 9801 – 1 = 198 numbers between them. Class 8 Mathematics Textbook Chapter ...
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Prime factorise 9408: 2⁶ × 3 × 7 × 7. To make it a perfect square, we need another 3. Multiply by 3 → 9408 × 3 = 28224. √28224 = 168. So, the smallest multiplier is 3. Class 8 Mathematics ...
The least common multiple (LCM) of 4, 9 and 10 is 180. The smallest square divisible by 180 is 900, since 30² = 900. So, the required smallest square number divisible by 4, 9 and 10 is 900. Class 8 Mathematics ...
To find the side, take the square root of 441. Since 21 × 21 = 441, the side length of the square is 21 meters. So, the side is 21 m. Class 8 NCERT Ganita Prakash Chapter 1 A Square and ...
Use identity: a³ – b³ = (a–b)(a² + ab + b²), a² – b² = (a–b)(a + b). (i) has largest numbers and cube difference. So, 67³ – 66³ is the greatest. Class 8 Mathematics Ganita Prakash A Square and A ...