NIOS on demand exams are for those who have already given exams once from any board. If someone is going to give ON DEMAND exams of any subject of class 12, it means he/she has already appeared once in 12th exams.
NIOS on demand exams are for those who have already given exams once from any board. If someone is going to give ON DEMAND exams of any subject of class 12, it means he/she has already appeared once in 12th exams.
सबसे बड़ी भुजा PR=4CM इसलिए सबसे बड़ा कोण Q है । सबसे छोटी भुजा PQ=2CM इसलिए सबसे छोटा कोण R है । क्योंकि सबसे बड़ी भुजा के सामने का कोण सबसे बड़ा होता है तथा सबसे छोटी भुजा के सामने का कोण सबसे छोटा छोटा होता है ।
सबसे बड़ी भुजा PR=4CM
इसलिए सबसे बड़ा कोण Q है ।
सबसे छोटी भुजा PQ=2CM
इसलिए सबसे छोटा कोण R है ।
क्योंकि सबसे बड़ी भुजा के सामने का कोण सबसे बड़ा होता है तथा सबसे छोटी भुजा के सामने का कोण सबसे छोटा छोटा होता है ।
You can take admission in NIOS Class 10 without any previous schooling. Visit to website: https://www.tiwariacademy.com/nios/nios-online-admission/ or call to Tiwari Academy for further assistance.
You can take admission in NIOS Class 10 without any previous schooling.
दिया है: m = 10 g = 0.01 kg u = 1000 m/s v = 0 m/s s = 20 m गति के द्वितीय समीकरण v^2 = u^2 + 2as से 0 = (1000)^2 + 2 x a x 20 0 = 1000000 + 40 a इसलिए a = 1000000/40 = 25000 m/s^2 गोली पर लगने वाला प्रतिरोधक बल F = ma = 0.01 x 25000 = 250 N गति के पहले समीकरण से v = u + at 0 = 1000 + 25000 t इसलिएRead more
दिया है:
m = 10 g = 0.01 kg
u = 1000 m/s
v = 0 m/s
s = 20 m
गति के द्वितीय समीकरण v^2 = u^2 + 2as से
0 = (1000)^2 + 2 x a x 20
0 = 1000000 + 40 a
इसलिए
a = 1000000/40 = 25000 m/s^2
गोली पर लगने वाला प्रतिरोधक बल
F = ma = 0.01 x 25000 = 250 N
गति के पहले समीकरण से
v = u + at
0 = 1000 + 25000 t
इसका परमाणु क्रमांक 18 है, इसलिए K L M 2 8 8 इसकी परमाणु संरचना बनाने के लिए पहले शेल में 2 इलेक्ट्रान, दूसरे शेल में 8 इलेक्ट्रान और तीसरे शेल में भी 8 इलेक्ट्रान बनाएं .
इसका परमाणु क्रमांक 18 है, इसलिए
K L M
2 8 8
इसकी परमाणु संरचना बनाने के लिए पहले शेल में 2 इलेक्ट्रान, दूसरे शेल में 8 इलेक्ट्रान और तीसरे शेल में भी 8 इलेक्ट्रान बनाएं .
Everyone can give exams of Class 10 without any previous schooling. You are eligible to give exam for class 10 in October 2020 if you fill the form before January 31, 2020. For mare information, visit to website: https://www.tiwariacademy.com/nios/nios-online-admission/ or call to Tiwari Academy offRead more
Everyone can give exams of Class 10 without any previous schooling. You are eligible to give exam for class 10 in October 2020 if you fill the form before January 31, 2020.
Viva questions for class 12 Economics are given on Tiwari Academy. Follow the link given below. https://www.tiwariacademy.com/viva-questions-class-12-economics/ On the same page links for Business Studies and Accountancy are also given. These questions are not only for viva but they come in CBSE BoaRead more
On the same page links for Business Studies and Accountancy are also given. These questions are not only for viva but they come in CBSE Board Exams also. These are basically important questions on subjects.
Can my daughter apply for on demand examination,she has not regesterd yet
NIOS on demand exams are for those who have already given exams once from any board. If someone is going to give ON DEMAND exams of any subject of class 12, it means he/she has already appeared once in 12th exams.
NIOS on demand exams are for those who have already given exams once from any board. If someone is going to give ON DEMAND exams of any subject of class 12, it means he/she has already appeared once in 12th exams.
See lessत्रिभुज PQR मेरे PQ=2CM,QR=3CM,PR=4CM त्रिभुज के सबसे बड़े और सबसे छोटे कोणो के नाम बताईये
सबसे बड़ी भुजा PR=4CM इसलिए सबसे बड़ा कोण Q है । सबसे छोटी भुजा PQ=2CM इसलिए सबसे छोटा कोण R है । क्योंकि सबसे बड़ी भुजा के सामने का कोण सबसे बड़ा होता है तथा सबसे छोटी भुजा के सामने का कोण सबसे छोटा छोटा होता है ।
सबसे बड़ी भुजा PR=4CM
इसलिए सबसे बड़ा कोण Q है ।
सबसे छोटी भुजा PQ=2CM
इसलिए सबसे छोटा कोण R है ।
क्योंकि सबसे बड़ी भुजा के सामने का कोण सबसे बड़ा होता है तथा सबसे छोटी भुजा के सामने का कोण सबसे छोटा छोटा होता है ।
See less12th class admission
There is no problem at all to take admission. It you take admission before March 15, 2020, you will be eligible to give exam in October 2020.
There is no problem at all to take admission. It you take admission before March 15, 2020, you will be eligible to give exam in October 2020.
See lessPower and exponent
(10)^2y = 25 So, [(10)^y]^2 = 25 and (10)^y = square root (25) = 5 Therefore, [10]^(-y) = 1/5
(10)^2y = 25
So,
[(10)^y]^2 = 25
and
(10)^y = square root (25) = 5
Therefore,
[10]^(-y) = 1/5
See lessPuzzle question 99.9% students and teacher not able to answer
Question need some modification. Because Apple is most costlier, that is of Re. 1. If we buy 100 apples, it will cost Rs. 100.
Question need some modification.
Because Apple is most costlier, that is of Re. 1.
If we buy 100 apples, it will cost Rs. 100.
See lessfor admission on class 10
You can take admission in NIOS Class 10 without any previous schooling. Visit to website: https://www.tiwariacademy.com/nios/nios-online-admission/ or call to Tiwari Academy for further assistance.
You can take admission in NIOS Class 10 without any previous schooling.
Visit to website:
https://www.tiwariacademy.com/nios/nios-online-admission/
or call to Tiwari Academy for further assistance.
See less10 गाम की एक गोली 10की घात 3 मी/सेकेण्ड के वेग से बालू के बोरे से टकराती है और 20 सेमी अन्दर धँस जाती है ज्ञात कीजिए (1) गोली पर लगने वाला पतिरोधात्मक अचर बल (2) गोली के इसथर होने मे लगा समय
दिया है: m = 10 g = 0.01 kg u = 1000 m/s v = 0 m/s s = 20 m गति के द्वितीय समीकरण v^2 = u^2 + 2as से 0 = (1000)^2 + 2 x a x 20 0 = 1000000 + 40 a इसलिए a = 1000000/40 = 25000 m/s^2 गोली पर लगने वाला प्रतिरोधक बल F = ma = 0.01 x 25000 = 250 N गति के पहले समीकरण से v = u + at 0 = 1000 + 25000 t इसलिएRead more
दिया है:
m = 10 g = 0.01 kg
u = 1000 m/s
v = 0 m/s
s = 20 m
गति के द्वितीय समीकरण v^2 = u^2 + 2as से
0 = (1000)^2 + 2 x a x 20
0 = 1000000 + 40 a
इसलिए
a = 1000000/40 = 25000 m/s^2
गोली पर लगने वाला प्रतिरोधक बल
F = ma = 0.01 x 25000 = 250 N
गति के पहले समीकरण से
v = u + at
0 = 1000 + 25000 t
इसलिए
See lesst = -1000/25000 = – 1/25 = -0.04 सेकेण्ड
तत्व का परमाणु क्रमांक 18 तथा द्रव्यमान संख्या 40 है। इसकी परमाणु संरचना का चित्र बनाइए ।
इसका परमाणु क्रमांक 18 है, इसलिए K L M 2 8 8 इसकी परमाणु संरचना बनाने के लिए पहले शेल में 2 इलेक्ट्रान, दूसरे शेल में 8 इलेक्ट्रान और तीसरे शेल में भी 8 इलेक्ट्रान बनाएं .
इसका परमाणु क्रमांक 18 है, इसलिए
K L M
2 8 8
इसकी परमाणु संरचना बनाने के लिए पहले शेल में 2 इलेक्ट्रान, दूसरे शेल में 8 इलेक्ट्रान और तीसरे शेल में भी 8 इलेक्ट्रान बनाएं .
See lessI have studied up to class 8th and I want to take direct admission in class 10th. How can I proceed further.
Everyone can give exams of Class 10 without any previous schooling. You are eligible to give exam for class 10 in October 2020 if you fill the form before January 31, 2020. For mare information, visit to website: https://www.tiwariacademy.com/nios/nios-online-admission/ or call to Tiwari Academy offRead more
Everyone can give exams of Class 10 without any previous schooling. You are eligible to give exam for class 10 in October 2020 if you fill the form before January 31, 2020.
For mare information, visit to website:
https://www.tiwariacademy.com/nios/nios-online-admission/
or call to Tiwari Academy officials for help.
See lessCbse exams 2020
Viva questions for class 12 Economics are given on Tiwari Academy. Follow the link given below. https://www.tiwariacademy.com/viva-questions-class-12-economics/ On the same page links for Business Studies and Accountancy are also given. These questions are not only for viva but they come in CBSE BoaRead more
Viva questions for class 12 Economics are given on Tiwari Academy. Follow the link given below.
https://www.tiwariacademy.com/viva-questions-class-12-economics/
On the same page links for Business Studies and Accountancy are also given. These questions are not only for viva but they come in CBSE Board Exams also. These are basically important questions on subjects.
See less