Base = 24 cm, Area = 192 cm² Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm Using Pythagorean theorem: x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400 x = √400 = 20 cm Perimeter = 2x + Base = 2(20) + 24 = 64 cm This question is based on Chapter 10, "Heron’s Formula," from the Class 9 NCERT MatRead more
Base = 24 cm, Area = 192 cm²
Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm
Using Pythagorean theorem:
x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400
x = √400 = 20 cm
Perimeter = 2x + Base = 2(20) + 24 = 64 cm
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
Longest side = 42 cm Semi-perimeter (s) = 48 cm Area = √[s(s-a)(s-b)(s-c)] = √[48(6)(14)(28)] = 336 cm² Using Area = (1/2) × base × height: 336 = (1/2) × 42 × h h = 336 / 21 = 16 cm This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. GivRead more
Longest side = 42 cm
Semi-perimeter (s) = 48 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[48(6)(14)(28)]
= 336 cm²
Using Area = (1/2) × base × height:
336 = (1/2) × 42 × h
h = 336 / 21 = 16 cm
This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. Give answer according to your understanding.
Using Heron's formula: Sides: a = 18 cm, b = 10 cm, c = 14 cm Semi-perimeter (s) = 21 cm Area = √[s(s-a)(s-b)(s-c)] = √[21(21-18)(21-10)(21-14)] = √[21 × 3 × 11 × 7] = 21√11 cm² This question is connected to Chapter 10, "Heron’s Formula," in the Class 9 NCERT Mathematics textbook. It focuses on applRead more
Using Heron’s formula:
Sides: a = 18 cm, b = 10 cm, c = 14 cm
Semi-perimeter (s) = 21 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[21(21-18)(21-10)(21-14)]
= √[21 × 3 × 11 × 7]
= 21√11 cm²
This question is connected to Chapter 10, “Heron’s Formula,” in the Class 9 NCERT Mathematics textbook. It focuses on applying Heron’s Formula to calculate the areas of triangles and quadrilaterals, not Probability. Provide your response based on the concepts from this chapter.
Sides: 8 cm, 11 cm, 13 cm Perimeter = 32 cm → Semi-perimeter (s) = 16 cm Area = √[s(s-a)(s-b)(s-c)] = √[16(16-8)(16-11)(16-13)] = √[16 × 8 × 5 × 3] = √1920 = 8√30 cm² This question is based on Chapter 10, "Heron’s Formula," from the Class 9 NCERT Mathematics textbook. It involves using Heron’s FormuRead more
Sides: 8 cm, 11 cm, 13 cm
Perimeter = 32 cm → Semi-perimeter (s) = 16 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[16(16-8)(16-11)(16-13)]
= √[16 × 8 × 5 × 3]
= √1920
= 8√30 cm²
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
The sides of the triangular plot are in the ratio 3:5:7, and the perimeter is 300 m. Let the sides be 3x, 5x, and 7x. From the perimeter: 3x + 5x + 7x = 300 → 15x = 300 → x = 20. Thus, the sides are: 3x = 60 m, 5x = 100 m, 7x = 140 m. The semi-perimeter (s) is: s = Perimeter / 2 = 300 / 2 = 150 m. URead more
The sides of the triangular plot are in the ratio 3:5:7, and the perimeter is 300 m. Let the sides be 3x, 5x, and 7x.
From the perimeter:
3x + 5x + 7x = 300 → 15x = 300 → x = 20.
Thus, the sides are:
3x = 60 m, 5x = 100 m, 7x = 140 m.
The semi-perimeter (s) is:
s = Perimeter / 2 = 300 / 2 = 150 m.
Using Heron’s formula for the area of a triangle:
Area = √[s(s-a)(s-b)(s-c)],
where a = 60 m, b = 100 m, c = 140 m.
Substitute the values:
Area = √[150(150-60)(150-100)(150-140)]
= √[150 × 90 × 50 × 10]
= √6750000.
Thus, the area of the triangle is 12√30 m².
This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. Give answer according to your understanding.
The base of an isosceles triangle is 24 cm and its area is 192 cm², then its perimeter is
Base = 24 cm, Area = 192 cm² Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm Using Pythagorean theorem: x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400 x = √400 = 20 cm Perimeter = 2x + Base = 2(20) + 24 = 64 cm This question is based on Chapter 10, "Heron’s Formula," from the Class 9 NCERT MatRead more
Base = 24 cm, Area = 192 cm²
Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm
Using Pythagorean theorem:
x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400
x = √400 = 20 cm
Perimeter = 2x + Base = 2(20) + 24 = 64 cm
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The height corresponding to the longest side of the triangle whose sides are 42 cm, 34 cm and 20 cm in length is
Longest side = 42 cm Semi-perimeter (s) = 48 cm Area = √[s(s-a)(s-b)(s-c)] = √[48(6)(14)(28)] = 336 cm² Using Area = (1/2) × base × height: 336 = (1/2) × 42 × h h = 336 / 21 = 16 cm This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. GivRead more
Longest side = 42 cm
Semi-perimeter (s) = 48 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[48(6)(14)(28)]
= 336 cm²
Using Area = (1/2) × base × height:
336 = (1/2) × 42 × h
h = 336 / 21 = 16 cm
This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Find the area of triangle two sides of which are 18cm and 10ccm and the perimeter is 42 cm.
Using Heron's formula: Sides: a = 18 cm, b = 10 cm, c = 14 cm Semi-perimeter (s) = 21 cm Area = √[s(s-a)(s-b)(s-c)] = √[21(21-18)(21-10)(21-14)] = √[21 × 3 × 11 × 7] = 21√11 cm² This question is connected to Chapter 10, "Heron’s Formula," in the Class 9 NCERT Mathematics textbook. It focuses on applRead more
Using Heron’s formula:
Sides: a = 18 cm, b = 10 cm, c = 14 cm
Semi-perimeter (s) = 21 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[21(21-18)(21-10)(21-14)]
= √[21 × 3 × 11 × 7]
= 21√11 cm²
This question is connected to Chapter 10, “Heron’s Formula,” in the Class 9 NCERT Mathematics textbook. It focuses on applying Heron’s Formula to calculate the areas of triangles and quadrilaterals, not Probability. Provide your response based on the concepts from this chapter.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 cm
Sides: 8 cm, 11 cm, 13 cm Perimeter = 32 cm → Semi-perimeter (s) = 16 cm Area = √[s(s-a)(s-b)(s-c)] = √[16(16-8)(16-11)(16-13)] = √[16 × 8 × 5 × 3] = √1920 = 8√30 cm² This question is based on Chapter 10, "Heron’s Formula," from the Class 9 NCERT Mathematics textbook. It involves using Heron’s FormuRead more
Sides: 8 cm, 11 cm, 13 cm
Perimeter = 32 cm → Semi-perimeter (s) = 16 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[16(16-8)(16-11)(16-13)]
= √[16 × 8 × 5 × 3]
= √1920
= 8√30 cm²
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The sides of a triangular plot are in the ratio of 3 : 5 : 7 and its perimeter is 300 m. Find its area.
The sides of the triangular plot are in the ratio 3:5:7, and the perimeter is 300 m. Let the sides be 3x, 5x, and 7x. From the perimeter: 3x + 5x + 7x = 300 → 15x = 300 → x = 20. Thus, the sides are: 3x = 60 m, 5x = 100 m, 7x = 140 m. The semi-perimeter (s) is: s = Perimeter / 2 = 300 / 2 = 150 m. URead more
The sides of the triangular plot are in the ratio 3:5:7, and the perimeter is 300 m. Let the sides be 3x, 5x, and 7x.
From the perimeter:
3x + 5x + 7x = 300 → 15x = 300 → x = 20.
Thus, the sides are:
3x = 60 m, 5x = 100 m, 7x = 140 m.
The semi-perimeter (s) is:
s = Perimeter / 2 = 300 / 2 = 150 m.
Using Heron’s formula for the area of a triangle:
Area = √[s(s-a)(s-b)(s-c)],
where a = 60 m, b = 100 m, c = 140 m.
Substitute the values:
Area = √[150(150-60)(150-100)(150-140)]
= √[150 × 90 × 50 × 10]
= √6750000.
Simplify the square root:
√6750000 = √(2² × 3³ × 5⁶) = 2 × 3¹.⁵ × 5³ = 12√30.
Thus, the area of the triangle is 12√30 m².
This question related to Chapter 10 Mathematics Class 9th NCERT. From the Chapter 10 Heron’s Formula. Probability. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/