1. (i) (3 + √3)(2 + √2) = 6 + 3√2 + 2√3 + 2√3 + √6

    (i) (3 + √3)(2 + √2) = 6 + 3√2 + 2√3 + 2√3 + √6

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  2. (ii) (3 + √3)(3 - √3) = 3² - (√3)² [∵ (a + b)(a - b) = a² - b²] = 9 - 3 = 6

    (ii) (3 + √3)(3 – √3) = 3² – (√3)² [∵ (a + b)(a – b) = a² – b²] = 9 – 3 = 6

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  3. (iii) (√5 + √2)² = (√5)² + (√2)² + 2 × √5 × √2 = 7 + 2√10 [∵ (a + b)² = a² + b² + 2ab]

    (iii) (√5 + √2)² = (√5)² + (√2)² + 2 × √5 × √2 = 7 + 2√10 [∵ (a + b)² = a² + b² + 2ab]

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  4. I studied this solution from NCERT solution for class 10 Maths. We know that, P(not E) = 1 - P(E) P(not E) =1- 0.05 = 0.95 Therefore, the probability of 'not E' is 0.95. Check the step by step solutions in the video here

    I studied this solution from NCERT solution for class 10 Maths.
    We know that, P(not E) = 1 – P(E)
    P(not E) =1- 0.05 = 0.95
    Therefore, the probability of ‘not E’ is 0.95.
    Check the step by step solutions in the video here

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