Choice (c) is correct. Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇ ⇒ 3r = r + 7 or 3r + ( r + 7) = 15 ⇒ 2r = 7 or 4r = 8 ⇒ r = 7/2 or r = 2 ⇒ r = 2 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more pleasRead more
Choice (c) is correct.
Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇
⇒ 3r = r + 7 or 3r + ( r + 7) = 15
⇒ 2r = 7 or 4r = 8
⇒ r = 7/2 or r = 2
⇒ r = 2
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (c) is correct. It is same as selecting 6 boys out of 11 boys or selecting 5 boys out of 11 boys. Number of ways of forming groups = ¹¹C₆ or ¹¹C₅ This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your undeRead more
Choice (c) is correct.
It is same as selecting 6 boys out of 11 boys or selecting 5 boys out of 11 boys.
Number of ways of forming groups = ¹¹C₆ or ¹¹C₅
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (b) is correct A parallelogram is formed by choosing 2 straight lines from the set of m parallel lines and 2 straight lines from the set of n parallel lines. Number of parallelograms = ᵐC₂ × ⁿC₂ = m(m - 1)/2 × n(n - 1)/2 This question related to Chapter 6 maths Class 11th NCERT. From the CRead more
Choice (b) is correct
A parallelogram is formed by choosing 2 straight lines from the set of m parallel lines and 2 straight lines from the set of n parallel lines.
Number of parallelograms = ᵐC₂ × ⁿC₂ = m(m – 1)/2 × n(n – 1)/2
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (b) is correct. Since the points lie on a circle, so on three points are collinear. Chord can be drawn by the combination of two points. Number of chords = ¹⁵ C ₂ = 15 × 14 / 1 × 2 = 105 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and CombinatiRead more
Choice (b) is correct.
Since the points lie on a circle, so on three points are collinear. Chord can be drawn by the combination of two points.
Number of chords = ¹⁵ C ₂ = 15 × 14 / 1 × 2 = 105
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈ n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more
Choice (a) is correct.
We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n
Given, ⁿC₁₂ = ⁿC₈
n = 12 + 8 ⇒ n = 20
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (b) is correct. Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more
Choice (b) is correct.
Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (c) is correct. Given, ∣ x -1 ∣ > 5 ⇒ (x - 1) 5 ⇒ x 5 + 1 ⇒ x 6 ⇒ x ∈ ( -∞, -4) ∪ (6, ∞) This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
Given, ∣ x -1 ∣ > 5
⇒ (x – 1) 5
⇒ x 5 + 1 ⇒ x 6
⇒ x ∈ ( -∞, -4) ∪ (6, ∞)
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
Choice (b) is correct. Given ∣ x ∣ < 3 ⇒ -3 < x < 3 This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaRead more
Choice (b) is correct.
Given ∣ x ∣ < 3 ⇒ -3 < x < 3
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
If ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇, then the value of r is
Choice (c) is correct. Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇ ⇒ 3r = r + 7 or 3r + ( r + 7) = 15 ⇒ 2r = 7 or 4r = 8 ⇒ r = 7/2 or r = 2 ⇒ r = 2 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more pleasRead more
Choice (c) is correct.
Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇
⇒ 3r = r + 7 or 3r + ( r + 7) = 15
⇒ 2r = 7 or 4r = 8
⇒ r = 7/2 or r = 2
⇒ r = 2
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
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If ⁿ ⁺ ¹C₃ = 3.ⁿ C₂, then the value of n is
Choice (d) is correct. Given, ⁿ ⁺ ¹C₃ = 3.ⁿ C₂ (n + 1)!/(n + 1 - 3)! × 3! = (3)× (n)!/ (n - 2)! × 2! ⇒ (n + 1) × (n)!/(n - 2)! ×3 ×2! = 3 × (n)!/(n-2)! × 2! ⇒ n + 1/3 = 3 ⇒ n + 1 = 9 ⇒ n = 8 Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanRead more
Choice (d) is correct.
Given, ⁿ ⁺ ¹C₃ = 3.ⁿ C₂
(n + 1)!/(n + 1 – 3)! × 3! = (3)× (n)!/ (n – 2)! × 2! ⇒ (n + 1) × (n)!/(n – 2)! ×3 ×2! = 3 × (n)!/(n-2)! × 2!
⇒ n + 1/3 = 3 ⇒ n + 1 = 9 ⇒ n = 8
Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
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The number of ways in which a group of 11 boys can be divided into two groups of 6 and 5 boys each is
Choice (c) is correct. It is same as selecting 6 boys out of 11 boys or selecting 5 boys out of 11 boys. Number of ways of forming groups = ¹¹C₆ or ¹¹C₅ This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your undeRead more
Choice (c) is correct.
It is same as selecting 6 boys out of 11 boys or selecting 5 boys out of 11 boys.
Number of ways of forming groups = ¹¹C₆ or ¹¹C₅
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If m parallel lines in a plane are intersected by a family of n parallel lines, the number of parallelogram formed is
Choice (b) is correct A parallelogram is formed by choosing 2 straight lines from the set of m parallel lines and 2 straight lines from the set of n parallel lines. Number of parallelograms = ᵐC₂ × ⁿC₂ = m(m - 1)/2 × n(n - 1)/2 This question related to Chapter 6 maths Class 11th NCERT. From the CRead more
Choice (b) is correct
A parallelogram is formed by choosing 2 straight lines from the set of m parallel lines and 2 straight lines from the set of n parallel lines.
Number of parallelograms = ᵐC₂ × ⁿC₂ = m(m – 1)/2 × n(n – 1)/2
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
The number of chords that can be drawn through 15 points on a circle is
Choice (b) is correct. Since the points lie on a circle, so on three points are collinear. Chord can be drawn by the combination of two points. Number of chords = ¹⁵ C ₂ = 15 × 14 / 1 × 2 = 105 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and CombinatiRead more
Choice (b) is correct.
Since the points lie on a circle, so on three points are collinear. Chord can be drawn by the combination of two points.
Number of chords = ¹⁵ C ₂ = 15 × 14 / 1 × 2 = 105
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ⁿP₃ = ⁿP₄ = 1 : 5, then the value of n is :
Choice (a) is correct Given, ⁿP₃ : ⁿP₄ = 1 : 5 ⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n - 4)!) = 1/5 ⇒ (n - 4)!/ (n -3)! = 1/5 ⇒ (n - 4)! / (n - 3) (n - 4)! = 1/5 ⇒ 1 / n - 3 = 1/5 ⇒ n - 3 = 5 ⇒ n = 8 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and CRead more
Choice (a) is correct
Given, ⁿP₃ : ⁿP₄ = 1 : 5
⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n – 4)!) = 1/5 ⇒ (n – 4)!/ (n -3)! = 1/5
⇒ (n – 4)! / (n – 3) (n – 4)! = 1/5 ⇒ 1 / n – 3 = 1/5
⇒ n – 3 = 5 ⇒ n = 8
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
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If ⁿC₁₂ = ⁿC₈, then the value of n is :
Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈ n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more
Choice (a) is correct.
We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n
Given, ⁿC₁₂ = ⁿC₈
n = 12 + 8 ⇒ n = 20
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
What is the value of n!/(n – r)! r! if n = 11 and r = 3?
Choice (b) is correct. Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more
Choice (b) is correct.
Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ∣ x – 1 ∣ > 5, then
Choice (c) is correct. Given, ∣ x -1 ∣ > 5 ⇒ (x - 1) 5 ⇒ x 5 + 1 ⇒ x 6 ⇒ x ∈ ( -∞, -4) ∪ (6, ∞) This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
Given, ∣ x -1 ∣ > 5
⇒ (x – 1) 5
⇒ x 5 + 1 ⇒ x 6
⇒ x ∈ ( -∞, -4) ∪ (6, ∞)
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-5
If x is a real number and ∣ x ∣ less than 3 then
Choice (b) is correct. Given ∣ x ∣ < 3 ⇒ -3 < x < 3 This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaRead more
Choice (b) is correct.
Given ∣ x ∣ < 3 ⇒ -3 < x < 3
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-5