Choice (d) is correct. The line is 2x - 7y = 13 Slope of the line, m = - coefficient of x / coefficient of y = -(2/-7) = 2/7 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: httpsRead more
Choice (d) is correct.
The line is 2x – 7y = 13
Slope of the line, m = – coefficient of x / coefficient of y = -(2/-7) = 2/7
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
Choice (a) is correct. Here, θ = 60° Slope of the line = m = tan 60° = √3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maRead more
Choice (a) is correct.
Here, θ = 60°
Slope of the line = m = tan 60° = √3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
Choice (b) is correct. Slope of the line AB = m = y₂ - y ₁/x₂ - x₁= -7 - 6/9 - 3 = -13/6 Slope of the line perpendicular to line AB = -1/m = 6/13 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more pleaRead more
Choice (b) is correct.
Slope of the line AB = m = y₂ – y ₁/x₂ – x₁= -7 – 6/9 – 3 = -13/6
Slope of the line perpendicular to line AB = -1/m = 6/13
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
Choice (c) is correct. Let the given points be P(3, -1) and Q(4, - 2). Slope of PQ = -2 + 1 /4 - 3 = -1/1 = -1 = m₁ and slope of x-axis = 0 = m₂ Let θ be the required angle between given lines. So, tan θ = m₂ - m₁ /1 + m₁m₂ = 0 + 1/1 - 0 = 1 ⇒ tan θ = tan 45° ⇒ θ = 45° This question related to ChapRead more
Choice (c) is correct.
Let the given points be P(3, -1) and Q(4, – 2).
Slope of PQ = -2 + 1 /4 – 3 = -1/1 = -1 = m₁
and slope of x-axis = 0 = m₂
Let θ be the required angle between given lines.
So, tan θ = m₂ – m₁ /1 + m₁m₂ = 0 + 1/1 – 0 = 1
⇒ tan θ = tan 45° ⇒ θ = 45°
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
Choice (b) is correct. Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5 Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer aRead more
Choice (b) is correct.
Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5
Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
The slope of the straight line 2x – 7y = 13 is
Choice (d) is correct. The line is 2x - 7y = 13 Slope of the line, m = - coefficient of x / coefficient of y = -(2/-7) = 2/7 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: httpsRead more
Choice (d) is correct.
The line is 2x – 7y = 13
Slope of the line, m = – coefficient of x / coefficient of y = -(2/-7) = 2/7
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the straight line, whose inclination with x-axis is 60° is
Choice (a) is correct. Here, θ = 60° Slope of the line = m = tan 60° = √3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maRead more
Choice (a) is correct.
Here, θ = 60°
Slope of the line = m = tan 60° = √3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the line perpendicular to the join of points A(3, 6) and B(9, -7) is
Choice (b) is correct. Slope of the line AB = m = y₂ - y ₁/x₂ - x₁= -7 - 6/9 - 3 = -13/6 Slope of the line perpendicular to line AB = -1/m = 6/13 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more pleaRead more
Choice (b) is correct.
Slope of the line AB = m = y₂ – y ₁/x₂ – x₁= -7 – 6/9 – 3 = -13/6
Slope of the line perpendicular to line AB = -1/m = 6/13
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The angle between x-axis and the line joining (3, -1) and (4, -2) is
Choice (c) is correct. Let the given points be P(3, -1) and Q(4, - 2). Slope of PQ = -2 + 1 /4 - 3 = -1/1 = -1 = m₁ and slope of x-axis = 0 = m₂ Let θ be the required angle between given lines. So, tan θ = m₂ - m₁ /1 + m₁m₂ = 0 + 1/1 - 0 = 1 ⇒ tan θ = tan 45° ⇒ θ = 45° This question related to ChapRead more
Choice (c) is correct.
Let the given points be P(3, -1) and Q(4, – 2).
Slope of PQ = -2 + 1 /4 – 3 = -1/1 = -1 = m₁
and slope of x-axis = 0 = m₂
Let θ be the required angle between given lines.
So, tan θ = m₂ – m₁ /1 + m₁m₂ = 0 + 1/1 – 0 = 1
⇒ tan θ = tan 45° ⇒ θ = 45°
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The intercepts cut by the line 3x + 5y = 15 on the x-axis and the y-axis are
Choice (b) is correct. Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5 Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer aRead more
Choice (b) is correct.
Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5
Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9