(a) 5m=60 Putting the given values in L.H.S., 5 x 10 = 50 ∵ L.H.S. ≠ R.H.S. ∴ m=10 is not the solution. 5 x 12 = 60 ∵ L.H.S. = R.H.S. ∴ m =12 is a solution. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) 5m=60
Putting the given values in L.H.S.,
5 x 10 = 50
∵ L.H.S. ≠ R.H.S.
∴ m=10 is not the solution.
5 x 12 = 60
∵ L.H.S. = R.H.S.
∴ m =12 is a solution.
(a) It is an equation of variable as both the sides are equal. The variable is x. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) It is an equation of variable as both the sides are equal. The variable is x.
Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation. 5m=60 (10, 5, 12, 15)
(a) 5m=60 Putting the given values in L.H.S., 5 x 10 = 50 ∵ L.H.S. ≠ R.H.S. ∴ m=10 is not the solution. 5 x 12 = 60 ∵ L.H.S. = R.H.S. ∴ m =12 is a solution. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) 5m=60
Putting the given values in L.H.S.,
5 x 10 = 50
∵ L.H.S. ≠ R.H.S.
∴ m=10 is not the solution.
5 x 12 = 60
∵ L.H.S. = R.H.S.
∴ m =12 is a solution.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessState which of the following are equations (with a variable). Given reason for your answer. Identify the variable from the equations with a variable. 17= x+7
(a) It is an equation of variable as both the sides are equal. The variable is x. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) It is an equation of variable as both the sides are equal. The variable is x.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See less(a) From expressions using t and 4. Use not more than one number operation. Every expression must have t in it. (b) Form expressions using y, 2 and 7. Every expression must have y in it. Use only two number operations. These should be different.
(a) t+4,t-4,4-t,4t,t/4,4/t (b) 2y+7,2y-7,7y+2,7y-2 and so on. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) t+4,t-4,4-t,4t,t/4,4/t
(b) 2y+7,2y-7,7y+2,7y-2 and so on.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessGive expression in the following cases:(a) 11 added to 2m. (b) 11 subtracted from 2m. (c) 5 times y to which 3 is added. (d) 5 times y from which 3 is subtracted. (e) y is multiplied by -8. (f) y is multiplied by -8 and then 5 is added to the result. (g) y is multiplied by 5 and result is subtracted from 16. (h) y is multiplied by -5 and the result is added to 16.
(a) 2m+11 (b) 2m-11 (c) 5y+3 (d) 5y-3 (e) -8y (f) -8y+5 (g) 16-5y (h) -5y+16 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) 2m+11 (b) 2m-11 (c) 5y+3 (d) 5y-3
(e) -8y (f) -8y+5 (g) 16-5y (h) -5y+16
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessGive expressions for the following cases: (a) 7 added to p. (b) 7 subtracted from p. (c) p multiplied by 7. (d) p divided by 7. (e) 7 subtracted from -m. (f) -p multiplied by 5. (g) -p divided by 5. (h) p multiplied by -5.
(a) 7+p (b) p-7 (c) 7p (d) p/7 (e) –m-7 (f) -5p (g) –p/5 (h) -5p https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) 7+p (b) p-7 (c) 7p (d) p/7
(e) –m-7 (f) -5p (g) –p/5 (h) -5p
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessIdentify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed: a+z, z-1, y+17, y-17
z+1→Addition y+17→Addition https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
z+1→Addition
y+17→Addition
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessWhich out of the following are expressions with numbers only: (a) Y+3 (b) (7×20)-8z (c) 5(21-7) +7×2 (d) 5 (e) 3x (f) 5-5n (g) (7×20)-(5×10)-45+p
(c) and (d) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(c) and (d)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessMake up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication. (Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), (5 x 8) + 7 make the other expressions)
(a) (8 x 5) – 7 (b) (8 + 5) – 7 (c) (8 x 7) – 5 (d) (8 + 7) – 5 (e) 5 x (7 + 8) (f) 5 + (7 x 8) (g) 5 + (8 – 7) (h) 5 – (7 + 8) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) (8 x 5) – 7
(b) (8 + 5) – 7
(c) (8 x 7) – 5
(d) (8 + 7) – 5
(e) 5 x (7 + 8)
(f) 5 + (7 x 8)
(g) 5 + (8 – 7)
(h) 5 – (7 + 8)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessTo find sum of three numbers 14, 27 and 13. We can have two ways. (a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54, or (b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus (14 + 27) + 13 = 14 + (27 + 13) This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables and ,ab . c
(a+b) + c = a+(b+c) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a+b) + c = a+(b+c)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessThe diameter of a circle is a line, which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure AB is a diameter of the circle; C is its centre). Express the diameter of the circle (d) in terms of its radius (r).
Since, length of diameter is double the length of radius. Therefore, d=2r https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Since, length of diameter is double the length of radius.
Therefore, d=2r
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See less