2(x+4) = 12 ⇒ x+4 = 12/2 ⇒ x+4 = 6 ⇒ x = 6-4 ⇒ x = 2 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
2(x+4) = 12
⇒ x+4 = 12/2
⇒ x+4 = 6
⇒ x = 6-4
⇒ x = 2
10p = 100 ⇒ 10p/10 = 100/10 [Dividing both sides by 10] ⇒ p=0 Class 7 Maths Chapter 4 Exercise 4.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
10p = 100
⇒ 10p/10 = 100/10 [Dividing both sides by 10]
⇒ p=0
3n-2 = 46 Step I: 3n-2+2=46+2 ⇒ 3n=48 [Adding 2 both sides] Step II: 3n/3 = 48/3 ⇒ n = 16 [Dividing both sides by 3] Class 7 Maths Chapter 4 Exercise 4.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
3n-2 = 46
Step I: 3n-2+2=46+2
⇒ 3n=48 [Adding 2 both sides]
Step II: 3n/3 = 48/3
⇒ n = 16 [Dividing both sides by 3]
Solve the following equations: 4 = 5 (p-2)
4 = 5 (p-2) ⇒ 4 = 5xp-5x2 ⇒ 4 = 5p - 10 ⇒ 5p-10 = 4 ⇒ 5p = 4 + 10 ⇒ 5p = 14 ⇒ p=14/5 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
4 = 5 (p-2)
⇒ 4 = 5xp-5×2
⇒ 4 = 5p – 10
⇒ 5p-10 = 4
⇒ 5p = 4 + 10
⇒ 5p = 14
⇒ p=14/5
Class 7 Maths Chapter 4 Exercise 4.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
Solve the following equations: 2(x+4) = 12
2(x+4) = 12 ⇒ x+4 = 12/2 ⇒ x+4 = 6 ⇒ x = 6-4 ⇒ x = 2 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
2(x+4) = 12
⇒ x+4 = 12/2
⇒ x+4 = 6
⇒ x = 6-4
⇒ x = 2
Class 7 Maths Chapter 4 Exercise 4.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
Solve the following equations: 2y+5/2 = 37/2
2y+5/2 = 37/2 ⇒ 2y = 37/2 - 5/2 ⇒ 2y = 37-5/2 ⇒ 2y =32/2 ⇒ 2y = 16 ⇒ y = 16/2 ⇒ y= 8 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
2y+5/2 = 37/2
⇒ 2y = 37/2 – 5/2
⇒ 2y = 37-5/2
⇒ 2y =32/2
⇒ 2y = 16
⇒ y = 16/2
⇒ y= 8
Class 7 Maths Chapter 4 Exercise 4.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
Solve the following equation: 10p = 100
10p = 100 ⇒ 10p/10 = 100/10 [Dividing both sides by 10] ⇒ p=0 Class 7 Maths Chapter 4 Exercise 4.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
10p = 100
⇒ 10p/10 = 100/10 [Dividing both sides by 10]
⇒ p=0
Class 7 Maths Chapter 4 Exercise 4.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
Give first the step you will use to separate the variable and then solve the equations: 3n-2 = 46
3n-2 = 46 Step I: 3n-2+2=46+2 ⇒ 3n=48 [Adding 2 both sides] Step II: 3n/3 = 48/3 ⇒ n = 16 [Dividing both sides by 3] Class 7 Maths Chapter 4 Exercise 4.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/
3n-2 = 46
Step I: 3n-2+2=46+2
⇒ 3n=48 [Adding 2 both sides]
Step II: 3n/3 = 48/3
⇒ n = 16 [Dividing both sides by 3]
Class 7 Maths Chapter 4 Exercise 4.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/