1. (a) 3 equations starting with x = 2. (i) x = 2 Multiplying both sides by 10, 10x = 20 Adding 2 both sides 10x + 2 = 20+2 = 10x+2 = 22 (ii) x = 2 Multiplying both sides by 5 5x = 10 Subtracting 3 from both sides 5x-3 = 10-3 = 5x-3 = 7 (iii) x = 2 Dividing both sides by 5 x/5 = 2/5 (b) 3 equations staRead more

    (a) 3 equations starting with x = 2.
    (i) x = 2
    Multiplying both sides by 10,
    10x = 20
    Adding 2 both sides
    10x + 2 = 20+2 = 10x+2 = 22

    (ii) x = 2
    Multiplying both sides by 5
    5x = 10
    Subtracting 3 from both sides
    5x-3 = 10-3 = 5x-3 = 7

    (iii) x = 2
    Dividing both sides by 5
    x/5 = 2/5

    (b) 3 equations starting with x = -2.
    (i) x = -2
    Multiplying both sides by 3
    3x=-6
    (ii) x = -2
    Multiplying both sides by 3
    3x=-6
    Adding 7 to both sides
    3x+7 = -6+7 = 3x+7 =1

    Class 7 Maths Chapter 4 Exercise 4.3

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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  2. 4 = 5 (p-2) ⇒ 4 = 5xp-5x2 ⇒ 4 = 5p - 10 ⇒ 5p-10 = 4 ⇒ 5p = 4 + 10 ⇒ 5p = 14 ⇒ p=14/5 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

    4 = 5 (p-2)
    ⇒ 4 = 5xp-5×2
    ⇒ 4 = 5p – 10
    ⇒ 5p-10 = 4
    ⇒ 5p = 4 + 10
    ⇒ 5p = 14
    ⇒ p=14/5

    Class 7 Maths Chapter 4 Exercise 4.3

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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    • 4
  3. 2(x+4) = 12 ⇒ x+4 = 12/2 ⇒ x+4 = 6 ⇒ x = 6-4 ⇒ x = 2 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

    2(x+4) = 12
    ⇒ x+4 = 12/2
    ⇒ x+4 = 6
    ⇒ x = 6-4
    ⇒ x = 2

    Class 7 Maths Chapter 4 Exercise 4.3

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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    • 4
  4. 2y+5/2 = 37/2 ⇒ 2y = 37/2 - 5/2 ⇒ 2y = 37-5/2 ⇒ 2y =32/2 ⇒ 2y = 16 ⇒ y = 16/2 ⇒ y= 8 Class 7 Maths Chapter 4 Exercise 4.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

    2y+5/2 = 37/2
    ⇒ 2y = 37/2 – 5/2
    ⇒ 2y = 37-5/2
    ⇒ 2y =32/2
    ⇒ 2y = 16
    ⇒ y = 16/2
    ⇒ y= 8

    Class 7 Maths Chapter 4 Exercise 4.3

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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  5. 10p = 100 ⇒ 10p/10 = 100/10 [Dividing both sides by 10] ⇒ p=0 Class 7 Maths Chapter 4 Exercise 4.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

    10p = 100
    ⇒ 10p/10 = 100/10 [Dividing both sides by 10]
    ⇒ p=0

    Class 7 Maths Chapter 4 Exercise 4.2

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-4/

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    • 5