Let p should be added. Then according to question, x²+xy+y²+p=2x²+3xy ⇒ p = 2x² + 3xy -(x²+xy+y²) ⇒ p = 2x² + 3xy -x²+xy-y² ⇒ p = 2x²- x² - y² + 3xy - xy ⇒ p = x² - y² +2xy Hence, x²-y²+2xy should be added. Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.coRead more
Let p should be added.
Then according to question,
x²+xy+y²+p=2x²+3xy
⇒ p = 2x² + 3xy -(x²+xy+y²)
⇒ p = 2x² + 3xy -x²+xy-y²
⇒ p = 2x²- x² – y² + 3xy – xy
⇒ p = x² – y² +2xy
Hence, x²-y²+2xy should be added.
y²-(-5y²) = y²+5y² = 6y² Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
3mn,-5mn,8mn-4mn = 3mn+(-5mn)+8mn+(-4mn) = (3-5+8-4)mn = 2mn Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Your answer is awaiting moderation. 21b-32+7b-20b = 21b+7b-20b-32 = 28b-20b-32 = 8b-32 Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Your answer is awaiting moderation.
21b-32+7b-20b = 21b+7b-20b-32
= 28b-20b-32 = 8b-32
S.No. Pair of terms Like / Unlike terms (i) 1.100 Like terms (ii) -7x,5/2x Like terms (iii) -29x,-29y Unlike terms Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
S.No. Pair of terms Like / Unlike terms
(i) 1.100 Like terms
(ii) -7x,5/2x Like terms
(iii) -29x,-29y Unlike terms
S.No. Expression Type of Polynomial (i) 4y - 7z Binomial (ii) y² Monomial (iii) x + y - xy Trinomial (iv) 100 Monomial Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
S.No. Expression Type of Polynomial
(i) 4y – 7z Binomial
(ii) y² Monomial
(iii) x + y – xy Trinomial
(iv) 100 Monomial
(a) S.No. Expression Term with factor x Coefficient of x (i) y²x+y y²x y² (ii) 13y²-8yx -8yx -8y (b) No. Expression Term contains y² Coefficient of y² (i) 8-xy² -xy² -x (ii) 5y²+7x 5y² 5 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/clRead more
(a)
S.No. Expression Term with factor x Coefficient of x
(i) y²x+y y²x y²
(ii) 13y²-8yx -8yx -8y
(b)
No. Expression Term contains y² Coefficient of y²
(i) 8-xy² -xy² -x
(ii) 5y²+7x 5y² 5
S.No. Expression Terms Numerical Coefficient (i) 5-3t² -3t² -3 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
(i) (a) x-3 Expression Terms Factors (ii) (a) -4x + 5 Terms: -4x,5 Factors: -4, x ; 5 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
(i) (a) x-3
Expression
Terms
Factors
(ii) (a) -4x + 5
Terms: -4x,5
Factors: -4, x ; 5
(i) y-z (ii) x+y/2 (iii) z² (iv)pq/4 (v) x²+y²(vi) 3mn+5 (vii) 10-yz (viii) ab-(a+b) Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
What should be added to x²+ 6xy+y² to obtain 2x²+3xy?
Let p should be added. Then according to question, x²+xy+y²+p=2x²+3xy ⇒ p = 2x² + 3xy -(x²+xy+y²) ⇒ p = 2x² + 3xy -x²+xy-y² ⇒ p = 2x²- x² - y² + 3xy - xy ⇒ p = x² - y² +2xy Hence, x²-y²+2xy should be added. Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.coRead more
Let p should be added.
Then according to question,
x²+xy+y²+p=2x²+3xy
⇒ p = 2x² + 3xy -(x²+xy+y²)
⇒ p = 2x² + 3xy -x²+xy-y²
⇒ p = 2x²- x² – y² + 3xy – xy
⇒ p = x² – y² +2xy
Hence, x²-y²+2xy should be added.
Class 7 Maths Chapter 12 Exercise 12.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Subtract: -5y² from y²
y²-(-5y²) = y²+5y² = 6y² Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
y²-(-5y²) = y²+5y²
= 6y²
Class 7 Maths Chapter 12 Exercise 12.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Add: 3mn, -5mn,8mn-4mn
3mn,-5mn,8mn-4mn = 3mn+(-5mn)+8mn+(-4mn) = (3-5+8-4)mn = 2mn Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
3mn,-5mn,8mn-4mn = 3mn+(-5mn)+8mn+(-4mn)
= (3-5+8-4)mn = 2mn
Class 7 Maths Chapter 12 Exercise 12.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Simplify combining like terms: 21b-32+7b-20b
Your answer is awaiting moderation. 21b-32+7b-20b = 21b+7b-20b-32 = 28b-20b-32 = 8b-32 Class 7 Maths Chapter 12 Exercise 12.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Your answer is awaiting moderation.
21b-32+7b-20b = 21b+7b-20b-32
= 28b-20b-32 = 8b-32
Class 7 Maths Chapter 12 Exercise 12.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
State whether a given pair of terms is of like or unlike terms: (i) 1, 100 (ii) -7x,5/2(x) (iii) -29x,-29y
S.No. Pair of terms Like / Unlike terms (i) 1.100 Like terms (ii) -7x,5/2x Like terms (iii) -29x,-29y Unlike terms Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
S.No. Pair of terms Like / Unlike terms
(i) 1.100 Like terms
(ii) -7x,5/2x Like terms
(iii) -29x,-29y Unlike terms
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Classify into monomials, binomials and trinomials: (i) 4y-7x (ii) y² (iii) x+y-xy (iv) 100
S.No. Expression Type of Polynomial (i) 4y - 7z Binomial (ii) y² Monomial (iii) x + y - xy Trinomial (iv) 100 Monomial Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
S.No. Expression Type of Polynomial
(i) 4y – 7z Binomial
(ii) y² Monomial
(iii) x + y – xy Trinomial
(iv) 100 Monomial
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
(a) Identify terms which contain x and give the coefficient of x. (i) y²x + y (ii) 13y²-8yx (b) Identify terms which contain y² and give the coefficient of y². (i) 8-xy² (ii) 5y²+7x
(a) S.No. Expression Term with factor x Coefficient of x (i) y²x+y y²x y² (ii) 13y²-8yx -8yx -8y (b) No. Expression Term contains y² Coefficient of y² (i) 8-xy² -xy² -x (ii) 5y²+7x 5y² 5 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/clRead more
(a)
S.No. Expression Term with factor x Coefficient of x
(i) y²x+y y²x y²
(ii) 13y²-8yx -8yx -8y
(b)
No. Expression Term contains y² Coefficient of y²
(i) 8-xy² -xy² -x
(ii) 5y²+7x 5y² 5
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
Identify the numerical coefficients of terms (other than constants) in the following expressions: 5-3t²
S.No. Expression Terms Numerical Coefficient (i) 5-3t² -3t² -3 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
S.No. Expression Terms Numerical Coefficient
(i) 5-3t² -3t² -3
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
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(i) Identify the terms and their factors in the following expressions, show the terms and factors by tree diagram: (a) x-3 (ii) Identify the terms and factors in the expressions given below: (a) -4x + 5
(i) (a) x-3 Expression Terms Factors (ii) (a) -4x + 5 Terms: -4x,5 Factors: -4, x ; 5 Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
(i) (a) x-3
Expression
Terms
Factors
(ii) (a) -4x + 5
Terms: -4x,5
Factors: -4, x ; 5
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
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Get the algebraic expressions in the following cases using variables, constants and arithmetic operations:(i) Subtraction of z from y.(ii) One-half of the sum of numbers x and y. (iii) The number z multiplied by itself. (iv) One-fourth of the product of numbers p and q. (v) Numbers x and y both squared and added. (vi) Number 5 added to three times the product of m and n. (vii) Product of numbers y and z subtracted from 10. (viii) Sum of numbers a and b subtracted from their product.
(i) y-z (ii) x+y/2 (iii) z² (iv)pq/4 (v) x²+y²(vi) 3mn+5 (vii) 10-yz (viii) ab-(a+b) Class 7 Maths Chapter 12 Exercise 12.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/
(i) y-z (ii) x+y/2 (iii) z²
(iv)pq/4 (v) x²+y²(vi) 3mn+5
(vii) 10-yz (viii) ab-(a+b)
Class 7 Maths Chapter 12 Exercise 12.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-12/