Using area = (1/2) x base x height = 60 with base 10 cm gives height h = 12 cm. In the half-triangle right triangle with legs 5 cm and 12 cm, hypotenuse is √(5² + 12²) = 13 cm.
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Virat
Asked: In: Class 9 Maths
The base is 40 – (15 + 15) = 10 cm. Semi-perimeter s = 20 cm. By Heron’s formula, area = √(20 x (20 – 15) x (20 – 15) x (20 – 10)) = √(20 x 5 x 5 ...
Virat
Asked: In: Class 9 Social Science
For (a + b)(a – b), remove corner square b² from square a²; rearrange the remaining L-shape into rectangle (a + b) by (a – b). For (a + b + c)², divide a square into 9 blocks yielding a² ...
Virat
Asked: In: Class 9 Maths
A regular hexagon consists of 6 equilateral triangles of side r, giving area 6 x (√3/4)r² = (3√3/2)r². Dividing by circle area πr² gives (3√3) / (2π) ≈ 0.827, which is twice Question 8’s ratio because its area is double.
Virat
Asked: In: Class 9 Maths
The square’s diagonal equals the circle’s diameter 2r. Area of the square is (1/2) x diagonal² = (1/2) x (2r)² = 2r². Dividing by circle area πr² gives the ratio 2 / π ≈ 0.637.