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How might Dr. Deepa Malik’s thought, ‘ability beyond disability’, serve as a guideline for success for all future para-athletes?
The maxim 'ability beyond disability' functions as a powerful mental foundation for aspiring para-athletes. Instead of being constrained by medical diagnoses or social pity, it shifts focus toward honing innate talents, athletic discipline and resilience. By identifying their strengths and viewing pRead more
The maxim ‘ability beyond disability’ functions as a powerful mental foundation for aspiring para-athletes. Instead of being constrained by medical diagnoses or social pity, it shifts focus toward honing innate talents, athletic discipline and resilience. By identifying their strengths and viewing physical obstacles merely as challenges to conquer, para-athletes can redefine boundaries, build self-belief and unlock extraordinary potential on the global competitive stage.
For more NCERT Solutions of Class 9 English Kaveri Chapter 5 The World of Limitless Possibilities Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/english/kaveri-chapter-5/
See lessA teacher mixes a large bag of sweets of different colours and randomly selects a sample of 30 sweets. She counts the number of sweets of each colour: 10 red sweets | 8 green sweets | 7 yellow sweets | 5 blue sweets (i) Calculate the probability that a randomly picked sweet from the sample is green. (ii) If there are 600 sweets in total in the large bag, estimate how many are likely to be yellow, based on the sample results.
Total sweets in sample = 30. (i) Number of green sweets = 8. Probability of picking a green sweet = Number of green sweets / Total sample sweets = 8 / 30 = 4 / 15 (approximately 0.267 or 26.7%). (ii) Number of yellow sweets in sample = 7. Probability of yellow sweet = 7 / 30. Total sweets in bag = 6Read more
Total sweets in sample = 30.
(i) Number of green sweets = 8.
Probability of picking a green sweet = Number of green sweets / Total sample sweets = 8 / 30 = 4 / 15 (approximately 0.267 or 26.7%).
(ii) Number of yellow sweets in sample = 7.
Probability of yellow sweet = 7 / 30.
Total sweets in bag = 600.
Estimated yellow sweets = (7 / 30) x 600 = 7 x 20 = 140.
Hence, an estimated 140 sweets are yellow.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/
See lessA survey is conducted at a school where a random sample of 40 students is asked about their favourite club. The responses are: 14 students: Science Club | 11 students: Arts Club | 9 students: Sports Club | 6 students: Debate Club. Assume there are 800 students in the whole school. (i) What is the probability that a randomly chosen student from the sample prefers the Arts Club? (ii) Using the sample results, estimate how many students in the whole school are likely to prefer the Sports Club.
Total students in the sample = 40. (i) Number of students preferring Arts Club = 11. Probability(Arts Club) = Number of Arts Club students / Total sample size = 11 / 40 = 0.275 (or 27.5%). (ii) Number of students preferring Sports Club in sample = 9. Probability(Sports Club) = 9 / 40. Total school pRead more
Total students in the sample = 40.
(i) Number of students preferring Arts Club = 11.
Probability(Arts Club) = Number of Arts Club students / Total sample size = 11 / 40 = 0.275 (or 27.5%).
(ii) Number of students preferring Sports Club in sample = 9.
Probability(Sports Club) = 9 / 40.
Total school population = 800.
Estimated students preferring Sports Club = (9 / 40) x 800 = 9 x 20 = 180.
Therefore, approximately 180 students prefer Sports Club.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/
See lessToss a coin 20 times and record the result each time (heads or tails). (i) How many times did you get heads? (ii) How many times did you get tails? (iii) Calculate the experimental probability of getting heads. (iv) If you toss the coin once more, what is the probability of getting tails?
This is a hands-on activity; taking a standard trial of 20 flips: (i) Number of heads obtained = 11. (ii) Number of tails obtained = 20 - 11 = 9. (iii) Experimental probability of heads = Number of heads / Total tosses = 11 / 20 = 0.55 (or 55%). (iv) If tossed once more, past tosses have no influencRead more
This is a hands-on activity; taking a standard trial of 20 flips:
(i) Number of heads obtained = 11.
(ii) Number of tails obtained = 20 – 11 = 9.
(iii) Experimental probability of heads = Number of heads / Total tosses = 11 / 20 = 0.55 (or 55%).
(iv) If tossed once more, past tosses have no influence because coin flips are independent events (avoiding Gambler’s Fallacy). The theoretical probability of tails remains 1 / 2 = 0.5 (or 50%).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/
See lessToss a paper cup into the air 100 times. After each toss record whether the cup lands on its bottom, upside down on its top or on its side (See Fig. 7.5). Assign probabilities to the outcomes by using experimental probability.
In an activity of 100 trials, suppose the observed landing frequencies are: Bottom lands = 7 times Top lands = 18 times Side lands = 75 times. Using the formula: Experimental Probability = Number of times the event occurred / Total trials P(bottom) = 7 / 100 = 0.07 (or 7%) P(top) = 18 / 100 = 0.18 (Read more
In an activity of 100 trials, suppose the observed landing frequencies are:
Bottom lands = 7 times
Top lands = 18 times
Side lands = 75 times.
Using the formula:
Experimental Probability = Number of times the event occurred / Total trials
P(bottom) = 7 / 100 = 0.07 (or 7%)
P(top) = 18 / 100 = 0.18 (or 18%)
P(side) = 75 / 100 = 0.75 (or 75%).
The sum of all experimental probabilities is 0.07 + 0.18 + 0.75 = 1.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/
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