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If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?
Suppose the width of the rectangle is x cm. According to the question, the length is three more than twice the width, so the length becomes 2x plus 3 cm. The perimeter of a rectangle is 2 multiplied by length plus width and it is given as 24 cm. Therefore, 2 multiplied by 2x plus 3 plus x equals 24.Read more
Suppose the width of the rectangle is x cm. According to the question, the length is three more than twice the width, so the length becomes 2x plus 3 cm. The perimeter of a rectangle is 2 multiplied by length plus width and it is given as 24 cm. Therefore, 2 multiplied by 2x plus 3 plus x equals 24. Simplifying gives 6x plus 6 equals 24, so x equals 3. Hence, the width is 3 cm and the length is 9 cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessBela has rupees 100 for pocket money. She spends 5 rupees every day. After how many days will she be left with rupees 40?
Bela has 100 rupees as pocket money and spends 5 rupees every day. Let the number of days be x. After x days, the amount left with her will be 100 minus 5x rupees. According to the question, she is left with 40 rupees. Therefore, we form the equation 100 minus 5x equals 40. Subtracting 100 from bothRead more
Bela has 100 rupees as pocket money and spends 5 rupees every day. Let the number of days be x. After x days, the amount left with her will be 100 minus 5x rupees. According to the question, she is left with 40 rupees. Therefore, we form the equation 100 minus 5x equals 40. Subtracting 100 from both sides gives minus 5x equals minus 60. Dividing by minus 5 gives x equal to 12. Hence, Bela will have 40 rupees after 12 days.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessPredict the number of squares in the next three stages of the pattern and write the sequence of numbers up to Stage 7 of the pattern
The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence fromRead more
The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence from Stage 1 to Stage 7 becomes 1, 3, 5, 7, 9, 11 and 13. This is called a linear pattern because the increase between consecutive terms remains constant.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessAn auto-rikshaw fare starts at rupees 25 and remains the same for the initial 2 km. Then it increases by rupees 15 per km. What will be the fare for a travel of 10 km?
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equalsRead more
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equals 120 rupees. Adding this to the fixed fare of 25 rupees, the total fare becomes 145 rupees for travelling 10 km.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA student has rupees 500 in her savings bank account. She gets rupees 150 every month as pocket money. How much money will she have at the end of every month from the second month onwards? Find a linear expression to represent the amount she will have in the nth month.
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represRead more
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represents the number of months, then the total amount after n months can be written as 500 plus 150n rupees. This is a linear expression because the increase is constant every month.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
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