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Check if 75 is divisible by 21 using prime factorization.
To determine divisibility, use prime factorizations: • 75 = 3 × 5² • 21 = 3 × 7 While both share the factor 3, 75 lacks the factor 7, which is required for divisibility. As a result, the prime factorization of 21 is not fully included in that of 75. Dividing confirms this: 75 ÷ 21 leaves a remainderRead more
To determine divisibility, use prime factorizations:
• 75 = 3 × 5²
• 21 = 3 × 7
While both share the factor 3, 75 lacks the factor 7, which is required for divisibility. As a result, the prime factorization of 21 is not fully included in that of 75. Dividing confirms this: 75 ÷ 21 leaves a remainder, proving that 75 is not divisible by 21.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
The teacher asked if 14560 is divisible by all of 2, 4, 5, 8, and 10. Guna checked for divisibility by only two of these numbers and declared it was divisible by all. What could those two numbers be?
Guna tested divisibility for 8 and 5 to conclude that 14560 is divisible by 2, 4, 5, 8, and 10. Divisibility by 8 ensures the number is divisible by 2 and 4, as 8 encompasses their factors. Similarly, divisibility by 5 guarantees divisibility by 10, since 10 = 2 × 5. These two tests are sufficient tRead more
Guna tested divisibility for 8 and 5 to conclude that 14560 is divisible by 2, 4, 5, 8, and 10. Divisibility by 8 ensures the number is divisible by 2 and 4, as 8 encompasses their factors. Similarly, divisibility by 5 guarantees divisibility by 10, since 10 = 2 × 5. These two tests are sufficient to confirm that the number is divisible by all five conditions without additional checks.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Which of the following numbers are divisible by all of 2, 4, 5, 8, and 10: 572, 2352, 5600, 6000, 77622160?
To be divisible by 2, 4, 5, 8, and 10, a number must be a multiple of their least common multiple (LCM), which is 40. Checking each: • 572: Not divisible by 8 or 40. • 2352: Not divisible by 5. • 5600: Divisible by 40. • 6000: Divisible by 40. • 77622160: Divisible by 40. Thus, 5600, 6000, and 77622Read more
To be divisible by 2, 4, 5, 8, and 10, a number must be a multiple of their least common multiple (LCM), which is 40. Checking each:
• 572: Not divisible by 8 or 40.
• 2352: Not divisible by 5.
• 5600: Divisible by 40.
• 6000: Divisible by 40.
• 77622160: Divisible by 40.
Thus, 5600, 6000, and 77622160 satisfy all conditions for divisibility by the given numbers.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Write two numbers whose product is 10000. The two numbers should not have 0 as the units digit.
To find two numbers whose product is 10000 without a 0 in their units digit, consider: • 25 and 400: 25 × 400 = 10000. Both end in non-zero digits (5 and 4), fulfilling the condition. While the product must equal 10000, ensuring no trailing zeroes in the individual numbers' digits limits valid combiRead more
To find two numbers whose product is 10000 without a 0 in their units digit, consider:
• 25 and 400: 25 × 400 = 10000.
Both end in non-zero digits (5 and 4), fulfilling the condition. While the product must equal 10000, ensuring no trailing zeroes in the individual numbers’ digits limits valid combinations, and this pair provides one such solution.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Find numbers between 330 and 340 that are divisible by 4.
To identify numbers divisible by 4 between 330 and 340, test each number for divisibility. Starting from 330: • 330 ÷ 4 = 82.5, not divisible. • 332 ÷ 4 = 83, divisible. • 336 ÷ 4 = 84, divisible. • 340 ÷ 4 = 85, outside the range. Thus, 332 and 336 are the only numbers in this interval that divideRead more
To identify numbers divisible by 4 between 330 and 340, test each number for divisibility. Starting from 330:
• 330 ÷ 4 = 82.5, not divisible.
• 332 ÷ 4 = 83, divisible.
• 336 ÷ 4 = 84, divisible.
• 340 ÷ 4 = 85, outside the range.
Thus, 332 and 336 are the only numbers in this interval that divide evenly by 4, meeting the criteria.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/