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A piece of string is 36 cm long. What will be the length of each side, if it is used to form: a. A square, b. A triangle with all sides of equal length, and c. A hexagon (a six sided closed figure) with sides of equal length?
a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What would be the cost of fencing a rectangular park whose length is 150 m and breadth is 120 m, if the fence costs `40 per metre?
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A farmer has a rectangular field having length 230 m and breadth 160 m. He wants to fence it with 3 rounds of rope as shown. What is the total length of rope needed?
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensurRead more
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensures enough rope to surround the field three times, securing the boundary effectively.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Akshi and Toshi start running along the rectangular tracks as shown in the figure. Akshi runs along the outer track and completes 5 rounds. Toshi runs along the inner track and completes 7 rounds. Now, they are wondering who ran more. Find out who ran the longer distance.
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi'sRead more
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi’s 1100 m. Toshi ran a longer distance overall.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Find out the total distance Akshi has covered in 5 rounds.
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exerciRead more
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exercise on the outer rectangular track.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/