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  1. For 5683, following the Kaprekar process: 1. Arrange digits: 8653 (largest) and 3568 (smallest). Subtract: 8653 − 3568 = 5085. 2. Repeat: 8550 − 0558 = 7992. 3. Finally: 9972 − 2799 = 6174. It takes three rounds to reach the Kaprekar constant, 6174. This process consistently converges to 6174 for anRead more

    For 5683, following the Kaprekar process:
    1. Arrange digits: 8653 (largest) and 3568 (smallest). Subtract: 8653 − 3568 = 5085.
    2. Repeat: 8550 − 0558 = 7992.
    3. Finally: 9972 − 2799 = 6174.
    It takes three rounds to reach the Kaprekar constant, 6174. This process consistently converges to 6174 for any 4-digit number (with non-identical digits), showcasing Kaprekar’s mathematical discovery.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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  2. They may lack immediate support from extended relatives during crises. Explanation: This highlights the trade-offs between independence and collective support. For more please visit here: https://www.tiwariacademy.com/ncert-solutions-class-6-social-science-chapter-9/

    They may lack immediate support from extended relatives during crises.
    Explanation: This highlights the trade-offs between independence and collective support.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions-class-6-social-science-chapter-9/

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    • 27
  3. With 1,500, 1,200, and 400 as options, 1,000 cannot be made, as these numbers don't combine precisely. However, numbers like 14,000 can be formed (1,200 × 10 + 400), 15,000 (1,500 × 10), and 16,000 (1,200 × 12 + 400). Exploring other combinations reveals gaps: some thousands cannot be achieved due tRead more

    With 1,500, 1,200, and 400 as options, 1,000 cannot be made, as these numbers don’t combine precisely. However, numbers like 14,000 can be formed (1,200 × 10 + 400), 15,000 (1,500 × 10), and 16,000 (1,200 × 12 + 400). Exploring other combinations reveals gaps: some thousands cannot be achieved due to limitations in available increments. This exercise highlights the constraints of arithmetic operations and the creative possibilities in making numbers.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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    • 28
  4. Grandparents provide wisdom, storytelling, homework help, and emotional support. Explanation: They enrich family life with their experience and guidance. For more please visit here: https://www.tiwariacademy.com/ncert-solutions-class-6-social-science-chapter-9/

    Grandparents provide wisdom, storytelling, homework help, and emotional support.
    Explanation: They enrich family life with their experience and guidance.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions-class-6-social-science-chapter-9/

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    • 27
  5. Starting with 25 in the Collatz sequence: 25 → 76 (25 × 3 + 1) → 38 (76 ÷ 2) → 19 → 58 → 29 → 88 → 44 → 22 → 11 → 34 → 17 → 52 → 26 → 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1. This fascinating pattern reaches 1 regardless of the starting number, supporting Collatz’s conjecture. However, the conjecRead more

    Starting with 25 in the Collatz sequence:
    25 → 76 (25 × 3 + 1) → 38 (76 ÷ 2) → 19 → 58 → 29 → 88 → 44 → 22 → 11 → 34 → 17 → 52 → 26 → 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1.
    This fascinating pattern reaches 1 regardless of the starting number, supporting Collatz’s conjecture. However, the conjecture remains unproven for all numbers, adding intrigue.

    For more NCERT Solutions for Class 6 Math Chapter 3 Number Play Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/

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