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  1. Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the periRead more

    Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the perimeter is 3 x 6 = 18 cm. This formula simplifies the calculation of the perimeter for all equilateral triangles, aiding in geometric studies and practical applications.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  2. For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle's boundary, helping in applications suRead more

    For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle’s boundary, helping in applications such as framing or fencing rectangular areas.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  3. Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), aRead more

    Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), and for circles, use 2 x π x radius. Understanding these calculations helps generalize perimeter formulas for all regular polygons like pentagons and hexagons.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  4. Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters haRead more

    Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters has an area of 6 x 4 = 24 square meters. Areas are expressed in square units like square meters.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  5. The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120Read more

    The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120 – 64 = 56 square meters. This represents the remaining land area available.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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