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What is regular polygons? Find perimeter of an equilateral triangle.
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the periRead more
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the perimeter is 3 x 6 = 18 cm. This formula simplifies the calculation of the perimeter for all equilateral triangles, aiding in geometric studies and practical applications.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Consider a rectangle ABCD whose length and breadth are 12 cm and 8 cm, respectively. What is its perimeter?
For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle's boundary, helping in applications suRead more
For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle’s boundary, helping in applications such as framing or fencing rectangular areas.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Find various objects from your surroundings that have regular shapes and find their perimeters. Also, generalise your understanding for the perimeter of other regular polygons.
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), aRead more
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), and for circles, use 2 x π x radius. Understanding these calculations helps generalize perimeter formulas for all regular polygons like pentagons and hexagons.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is an area? Find area of a square and area of a rectangle.
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters haRead more
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters has an area of 6 x 4 = 24 square meters. Areas are expressed in square units like square meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Four square flower beds each of side 4 m are in four corners on a piece of land 12 m long and 10 m wide. Find the area of the remaining part of the land.
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120Read more
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120 – 64 = 56 square meters. This represents the remaining land area available.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/