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Jeevika takes 10/3 minutes to take a complete round of the park and her friend Namit takes 13/4 minutes to do the same. Who takes less time and by how much?
To compare the times, convert 10/3 and 13/4 to a common denominator. The least common denominator is 12. Convert 10/3 to 40/12 and 13/4 to 39/12. Now, compare: 39/12 < 40/12, so Namit takes less time. The difference is: 40/12 – 39/12 = 1/12. Thus, Namit takes 1/12 of a minute less than Jeevika, wRead more
To compare the times, convert 10/3 and 13/4 to a common denominator. The least common denominator is 12. Convert 10/3 to 40/12 and 13/4 to 39/12. Now, compare:
39/12 < 40/12, so Namit takes less time.
The difference is:
40/12 – 39/12 = 1/12.
Thus, Namit takes 1/12 of a minute less than Jeevika, which equals 5 seconds. This method ensures accurate comparison by aligning the fractions and observing the difference in time.
For more NCERT Solutions for Class 6 Math Chapter 7 Fractions Extra Questions and Answer:
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Jaya’s school is 7/10 km from her home. She takes an auto for 1/2 km from her home daily, and then walks the remaining distance to reach her school. How much does she walk daily to reach the school?
Jaya’s school is 7/10 km away, and she takes an auto for 1/2 km. To find the distance she walks, subtract 1/2 from 7/10. First, convert 1/2 to 5/10. Now, subtract: 7/10 – 5/10 = 2/10, which simplifies to 1/5. Therefore, Jaya walks 1/5 km daily. This method ensures that the distances are aligned usinRead more
Jaya’s school is 7/10 km away, and she takes an auto for 1/2 km. To find the distance she walks, subtract 1/2 from 7/10. First, convert 1/2 to 5/10. Now, subtract:
7/10 – 5/10 = 2/10, which simplifies to 1/5.
Therefore, Jaya walks 1/5 km daily. This method ensures that the distances are aligned using a common denominator, and the result is simplified to its lowest terms, representing the portion she walks each day.
For more NCERT Solutions for Class 6 Math Chapter 7 Fractions Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/
What is the Brahmagupta’s method for subtracting two fractions?
Brahmagupta’s method for subtracting fractions starts with finding a common denominator, typically by multiplying the denominators or finding the least common multiple. Once the fractions are converted to have the same denominator, subtract the numerators while keeping the denominator unchanged. IfRead more
Brahmagupta’s method for subtracting fractions starts with finding a common denominator, typically by multiplying the denominators or finding the least common multiple. Once the fractions are converted to have the same denominator, subtract the numerators while keeping the denominator unchanged. If necessary, simplify the result by dividing both the numerator and denominator by their greatest common factor. This method allows for accurate and simplified subtraction, ensuring proper handling of fractions with different denominators.
For more NCERT Solutions for Class 6 Math Chapter 7 Fractions Extra Questions and Answer:
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Geeta bought 2/5 meter of lace and Shamim bought 3/4 meter of the same lace to put a complete border on a table cloth whose perimeter is 1 meter long. Find the total length of the lace they both have bought. Will the lace be sufficient to cover the whole border?
To determine if the lace is sufficient, add 2/5 and 3/4. The common denominator is 20. Convert 2/5 to 8/20 and 3/4 to 15/20. Adding the fractions gives: 8/20 + 15/20 = 23/20. This simplifies to 1 3/20 meters, which is greater than the 1-meter perimeter. Therefore, Geeta and Shamim's lace is more thaRead more
To determine if the lace is sufficient, add 2/5 and 3/4. The common denominator is 20. Convert 2/5 to 8/20 and 3/4 to 15/20. Adding the fractions gives:
8/20 + 15/20 = 23/20.
This simplifies to 1 3/20 meters, which is greater than the 1-meter perimeter. Therefore, Geeta and Shamim’s lace is more than enough to cover the tablecloth’s border. This calculation shows how adding fractions with different denominators gives the required total.
For more NCERT Solutions for Class 6 Math Chapter 7 Fractions Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/
What are shrubs, and can you give an example?
Shrubs are plants with woody stems that branch near the ground. Their stems are hard but thinner than tree trunks. An example of a shrub is the rose plant, which exhibits these characteristics, making it distinct from herbs and trees. For more visit here: https://www.tiwariacademy.com/ncert-solutionRead more
Shrubs are plants with woody stems that branch near the ground. Their stems are hard but thinner than tree trunks. An example of a shrub is the rose plant, which exhibits these characteristics, making it distinct from herbs and trees.
For more visit here:
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