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A car starts from rest and accelerates uniformly at 5m/s². What will be its velocity after 4 seconds?
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values: v = 0 + 5 × 4 = 20 m/s. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values:
v = 0 + 5 × 4 = 20 m/s.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A particle is confined to rotate in a circular path with decreasing liner speed. Then which of the following is correct?
When a particle moves in a circular path with decreasing linear speed, it experiences a tangential acceleration directed opposite to its velocity, causing it to slow down. This deceleration results in a reduction of the particle's angular momentum over time. Thus, the angular momentum of the particlRead more
When a particle moves in a circular path with decreasing linear speed, it experiences a tangential acceleration directed opposite to its velocity, causing it to slow down. This deceleration results in a reduction of the particle’s angular momentum over time. Thus, the angular momentum of the particle is not conserved in this scenario.
If the speed of the particle were constant, then it would only have centripetal acceleration toward the center of the circle, so it would have a constant angular momentum. In this case, the existence of tangential acceleration means that the speed of the particle, and hence its angular momentum, will change.
Therefore, the correct statement is that the angular momentum of the particle is not conserved while it moves in a circular path with decreasing linear speed.
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See lessWhat is the equation for the final velocity of an object moving with uniform acceleration?
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
How does Dhārana differ from regular concentration?
Dhārana, the sixth limb of Ashtāṅga Yoga, surpasses regular concentration by emphasizing sustained, uninterrupted focus on a single object or idea. While ordinary concentration may waver, Dhārana cultivates deeper mental discipline, enabling prolonged attention. This practice calms distractions, fosRead more
Dhārana, the sixth limb of Ashtāṅga Yoga, surpasses regular concentration by emphasizing sustained, uninterrupted focus on a single object or idea. While ordinary concentration may waver, Dhārana cultivates deeper mental discipline, enabling prolonged attention. This practice calms distractions, fosters inner tranquility, and prepares the mind for meditation (Dhyāna). By strengthening cognitive abilities and emotional control, Dhārana is a transformative step in achieving mental clarity and spiritual growth.
See lessWhat represent in the slope of a velocity-time graph?
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according toRead more
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/