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bhawna jain
bhawna jain
See lessWhich of the following cell organelle forms lysosome?
(d) Lysosomes bud off as vesicles from Golgi apparatus. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
(d) Lysosomes bud off as vesicles from Golgi apparatus.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
See lessThere are 3 different rings to be worn in four fingers with at most one in each finger. Find the number of ways in which it can be done.
Choice (b) is correct. 3 different rings to be worn in four fingers with at most one in each finger in P(4, 3) ways = 4!/(4 - 3)! = 4!/1! = 4 × 3 × 2 × 1/1 = 24 This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to yourRead more
Choice (b) is correct.
3 different rings to be worn in four fingers with at most one in each finger in P(4, 3) ways = 4!/(4 – 3)! = 4!/1! = 4 × 3 × 2 × 1/1 = 24
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇, then the value of r is
Choice (c) is correct. Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇ ⇒ 3r = r + 7 or 3r + ( r + 7) = 15 ⇒ 2r = 7 or 4r = 8 ⇒ r = 7/2 or r = 2 ⇒ r = 2 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more pleasRead more
Choice (c) is correct.
Given ¹⁵ C₃ᵣ = ¹⁵ Cᵣ ₊ ₇
⇒ 3r = r + 7 or 3r + ( r + 7) = 15
⇒ 2r = 7 or 4r = 8
⇒ r = 7/2 or r = 2
⇒ r = 2
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ⁿ ⁺ ¹C₃ = 3.ⁿ C₂, then the value of n is
Choice (d) is correct. Given, ⁿ ⁺ ¹C₃ = 3.ⁿ C₂ (n + 1)!/(n + 1 - 3)! × 3! = (3)× (n)!/ (n - 2)! × 2! ⇒ (n + 1) × (n)!/(n - 2)! ×3 ×2! = 3 × (n)!/(n-2)! × 2! ⇒ n + 1/3 = 3 ⇒ n + 1 = 9 ⇒ n = 8 Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanRead more
Choice (d) is correct.
Given, ⁿ ⁺ ¹C₃ = 3.ⁿ C₂
(n + 1)!/(n + 1 – 3)! × 3! = (3)× (n)!/ (n – 2)! × 2! ⇒ (n + 1) × (n)!/(n – 2)! ×3 ×2! = 3 × (n)!/(n-2)! × 2!
⇒ n + 1/3 = 3 ⇒ n + 1 = 9 ⇒ n = 8
Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6