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  1. Choice (c) is correct. We have, (1 + x + x²)ⁿ = a₀ + a₁x + a₂x² + a₃x³ + .... + a₂ₙx²ⁿ Putting x = 1 and - 1 in (1), we get  1 = a₀ + a₁ + a₂ + a₃ + .... a₂ₙ and 3ⁿ  = a₀ + a₁x + a₂x² + a₃x³ + .... + a₂ₙ Subtracting (3) from (2), we get 1 - 3ⁿ = 2(a₁ + a₃ + a₅ .... +a₂ₙ ₋ ₁) ⇒ a₁ + a₃ + a₅ .... +a₂ₙRead more

    Choice (c) is correct.
    We have, (1 + x + x²)ⁿ = a₀ + a₁x + a₂x² + a₃x³ + …. + a₂ₙx²ⁿ
    Putting x = 1 and – 1 in (1), we get 
    1 = a₀ + a₁ + a₂ + a₃ + …. a₂ₙ
    and 3ⁿ  = a₀ + a₁x + a₂x² + a₃x³ + …. + a₂ₙ
    Subtracting (3) from (2), we get
    1 – 3ⁿ = 2(a₁ + a₃ + a₅ …. +a₂ₙ ₋ ₁)
    ⇒ a₁ + a₃ + a₅ …. +a₂ₙ ₋ ₁ = 1 – 3ⁿ/ 2
    This question related to Chapter 7 maths Class 11th NCERT. From the Chapter 7: Binomial Theorem. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-7

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    • 7
  2. Choice (c) is correct. We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1). Total number of terms in the expansion of (1 + x)¹⁰⁰¹ is (1001 + 1) = 1002. Total number of terms in the expansion of (1 + x) ¹⁰⁰¹ -x¹⁰⁰¹ is 1001 as two terms cancel each other This question relateRead more

    Choice (c) is correct.
    We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1).
    Total number of terms in the expansion of (1 + x)¹⁰⁰¹ is (1001 + 1) = 1002.
    Total number of terms in the expansion of (1 + x) ¹⁰⁰¹ -x¹⁰⁰¹ is 1001 as two terms cancel each other
    This question related to Chapter 7 maths Class 11th NCERT. From the Chapter 7: Binomial Theorem. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-7

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    • 14
  3. Choice (a) is correct. We have, (a³ -3a²b + 3ab² - b³)⁵⁰ = {(a - b)³}⁵⁰ = (a - b)¹⁵⁰ We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1). Total number of terms in the expansion of (a - b)¹⁵⁰ is (150 + 1) = 151. Total number of terms in the expansion of (a³ - 3a²b + 3ab² -Read more

    Choice (a) is correct.
    We have, (a³ -3a²b + 3ab² – b³)⁵⁰ = {(a – b)³}⁵⁰ = (a – b)¹⁵⁰
    We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1).
    Total number of terms in the expansion of (a – b)¹⁵⁰ is (150 + 1) = 151.
    Total number of terms in the expansion of (a³ – 3a²b + 3ab² – b³)⁵⁰ is 151.
    This question related to Chapter 7 maths Class 11th NCERT. From the Chapter 7: Binomial Theorem. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-7

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    • 5
  4. Choice (c) is correct We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1). Total number of terms in the expansion of (x + a)⁵⁰¹ is (501 + 1) = 502. Total number of terms in the expansion of (x + a)⁵⁰¹ + (x - a)⁵⁰¹ is 251 terms get cancelled. This question related to ChapteRead more

    Choice (c) is correct
    We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1).
    Total number of terms in the expansion of (x + a)⁵⁰¹ is (501 + 1) = 502.
    Total number of terms in the expansion of (x + a)⁵⁰¹ + (x – a)⁵⁰¹ is 251 terms get cancelled.
    This question related to Chapter 7 maths Class 11th NCERT. From the Chapter 7: Binomial Theorem. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-7

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    • 16