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Alloys are mixtures of (i) two metals. (ii) a metal and a non-metal. (iii) two non-metals. (iv) a metal and mercury.
The correct answer is (c) (i) and (iv). https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/
The correct answer is (c) (i) and (iv).
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/
See lessDuring a chemical change, the
Chemical properties of a substance change and Physical properties of a substance change. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/
Chemical properties of a substance change and Physical properties of a substance change.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/
See lessGiven that A is a square matrix of order 3 and |A| = -4, then |adj. A| is equal to:
We are given that A is a square matrix of order 3 and |A| = -4. We are asked to find the value of |adj(A)|. The formula for the determinant of the adjugate matrix adj(A) for a square matrix A of order n is |adj(A)| = |A|^(n-1) For a matrix of order 3, n = 3. Hence, the above formula becomes |adj(A)|Read more
We are given that A is a square matrix of order 3 and |A| = -4. We are asked to find the value of |adj(A)|.
The formula for the determinant of the adjugate matrix adj(A) for a square matrix A of order n is
|adj(A)| = |A|^(n-1)
For a matrix of order 3, n = 3. Hence, the above formula becomes
|adj(A)| = |A|^(3-1) = |A|²
We know that |A| = -4. So,
|adj(A)| = (-4)² = 16
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Degree of the differential equation sin x + cos (dy/dx) = y² is
The differential equation given is: sin(x) + cos(dy/dx) = y² To know the degree of the differential equation, we have the following steps: 1. Rearrange the formula: The formula contains dy/dx that is not raised to any power directly. However, with the term cos(dy/dx) the degree calculation is compliRead more
The differential equation given is:
sin(x) + cos(dy/dx) = y²
To know the degree of the differential equation, we have the following steps:
1. Rearrange the formula: The formula contains dy/dx that is not raised to any power directly. However, with the term cos(dy/dx) the degree calculation is complicated since it deals with a trigonometric function of the derivative.
2. Degree of a differential equation: The degree of a differential equation is defined to be the highest power of the highest-order derivative after the equation has been made free from any irrational terms, fractional powers, or trigonometric functions involving derivatives.
3. This equation contains a trigonometric function, cos(dy/dx), whose argument is a first derivative, not an algebraic expression, not a polynomial, not a simple rational term. Since it’s placed within the argument of a trigonometric function, the degree is undefined.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-9
The general solution of rhe differential equation ydx -xdy = 0; (Given x, y > 0), is of the form
The given differential equation is: y dx - x dy = 0 This is a first-order linear differential equation. We can rewrite it as: y dx = x dy Now, divide both sides by x and y: (dx/x) = (dy/y) This is a separable differential equation, meaning we can integrate both sides separately. Integrating both sidRead more
The given differential equation is:
y dx – x dy = 0
This is a first-order linear differential equation. We can rewrite it as:
y dx = x dy
Now, divide both sides by x and y:
(dx/x) = (dy/y)
This is a separable differential equation, meaning we can integrate both sides separately.
Integrating both sides:
∫(1/x) dx = ∫(1/y) dy
The integrals of 1/x and 1/y are:
ln|x| = ln|y| + C
Now, take both sides as exponents to get rid of the logarithms:
x = C y
Therefore, the general solution is:
y = cx
where c is a constant.
So, the right answer is y = cx.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-4