Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.
If f(x) = cos² x + sec ² x, then
Choice (a) is correct. Given that, f(x) = cos² x + sec² x We know that, A.M ≥ G.M (cos² x + sec ² x)/2 ≥ √cos² x. sec ² x ⇒ cos² x + sec ² x ≥ 2 ⇒ f(x) ≥ 2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understaRead more
Choice (a) is correct.
Given that, f(x) = cos² x + sec² x
We know that, A.M ≥ G.M
(cos² x + sec ² x)/2 ≥ √cos² x. sec ² x
⇒ cos² x + sec ² x ≥ 2
⇒ f(x) ≥ 2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of cos 25° 35′ cos34° 25′ – sin 25° 34′ sin 34°’ 25′ is
Choice (d) is correct. cos 25° 35' cos 34° 25' - sin25° 35' sin 34°' 25' = cos(25° 35' + 34° 25') = cos 60° = 1/2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://wRead more
Choice (d) is correct.
cos 25° 35′ cos 34° 25′ – sin25° 35′ sin 34°’ 25′ = cos(25° 35′ + 34° 25′) = cos 60° = 1/2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
Period of cosecant function is
Choice (a) is correct. Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaptRead more
Choice (a) is correct.
Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of 64 π is
Choice (c) is correct. sin 64 π = sin (2π × 32 + 0) = sin 0 = 0 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/matRead more
Choice (c) is correct.
sin 64 π = sin (2π × 32 + 0) = sin 0 = 0
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of tan 1° tan 2° tan 3° ….. tan89° is equal to
Choice (b) is correct tan 1° tan 2° tan 3° ..... tan89° = (tan 1° tan89°) (tan 2° tan 88°)....(tan 44° tan 46°) tan 45° = {tan 1° tan (90° - 1°)} {tan 2° tan (90° - 2°)}..... {tan 44° tan (90° - 44°)} tan 45° = (tan 1° cot 1°) (tan 2° cot 2°).... (tan 44° cot 44°) tan45° = (1) (1)...(1)(1) = 1 ThisRead more
Choice (b) is correct tan 1° tan 2° tan 3° ….. tan89° = (tan 1° tan89°) (tan 2° tan 88°)….(tan 44° tan 46°) tan 45°
= {tan 1° tan (90° – 1°)} {tan 2° tan (90° – 2°)}….. {tan 44° tan (90° – 44°)} tan 45°
= (tan 1° cot 1°) (tan 2° cot 2°)…. (tan 44° cot 44°) tan45°
= (1) (1)…(1)(1) = 1
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3