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The value of i¹⁰⁰² is
Choice (b) is correct. i¹⁰⁰² = i¹⁰⁰⁰ × i² = (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.cRead more
Choice (b) is correct.
i¹⁰⁰² = i¹⁰⁰⁰ × i²
= (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
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Which of the following options define imaginary number?
Choice (c) is correct. We know that the square root of negative number is imaginary number. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Choice (c) is correct. We know that the square root of negative number is imaginary number.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-4
An atom with 3 protons and 4 neutrons will have a valency of
(c) An atom with 3 protons and 4 neutrons (lithium) will have a valency of 1. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/
(c) An atom with 3 protons and 4 neutrons (lithium) will have a valency of 1.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/
See lessIf the minimum value of an objective function Z = ax + by occurs at two points (3, 4) and (4, 3), then
Given the objective function Z = ax + by, the minimum value occurs at two points (3, 4) and (4, 3). 1. At point (3, 4), the objective function is Z = a(3) + b(4) = 3a + 4b. 2. At point (4, 3), the objective function is Z = a(4) + b(3) = 4a + 3b. Since both points give the minimum value of Z, the objRead more
Given the objective function Z = ax + by, the minimum value occurs at two points (3, 4) and (4, 3).
1. At point (3, 4), the objective function is Z = a(3) + b(4) = 3a + 4b.
2. At point (4, 3), the objective function is Z = a(4) + b(3) = 4a + 3b.
Since both points give the minimum value of Z, the objective function at these points must be equal:
3a + 4b = 4a + 3b
Solving for a and b:
3a + 4b – 4a – 3b = 0
-a + b = 0 ⟹ a = b
Thus, the correct condition is a = b.
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If a + ib = c + id, then
Choice (d) is correct. Given, a + ib = c +id ⇒ a = c and b = d ⇒ a² + b² = c² + d² This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacadRead more
Choice (d) is correct.
Given, a + ib = c +id
⇒ a = c and b = d
⇒ a² + b² = c² + d²
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-4