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  1. The sample space of candies in the bag is: S = {strawberry, lemon, mint} Total number of possible outcomes = 3. The event E consists of picking a strawberry candy: E = {strawberry} Number of favourable outcomes = 1. Using the formula for theoretical probability: P(E) = Number of favourable outcomesRead more

    The sample space of candies in the bag is:

    S = {strawberry, lemon, mint}

    Total number of possible outcomes = 3.

    The event E consists of picking a strawberry candy:

    E = {strawberry}

    Number of favourable outcomes = 1.

    Using the formula for theoretical probability:

    P(E) = Number of favourable outcomes / Total possible outcomes

    P(strawberry candy) = 1 / 3 (which is approximately 0.333 or 33.3%).

    Hence, the probability is 1 / 3.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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  2. (i) Not equally likely: A normal working car usually starts, depending on mechanical condition rather than pure chance. (ii) Equally likely: A fair coin is balanced, giving heads and tails an equal chance of 1/2 each. (iii) Equally likely: A fair 6-sided die gives each number from 1 to 6 an identicaRead more

    (i) Not equally likely: A normal working car usually starts, depending on mechanical condition rather than pure chance.

    (ii) Equally likely: A fair coin is balanced, giving heads and tails an equal chance of 1/2 each.

    (iii) Equally likely: A fair 6-sided die gives each number from 1 to 6 an identical probability of 1/6.

    (iv) Not equally likely: Blue marbles (7) outnumber red marbles (3), making blue more likely.

    (v) Equally likely: Biologically, a newborn being a boy or a girl is equally likely with probability 1/2.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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    • 21
  3. The blank for the concept is filled by 'relative frequency'. The blank for the value is filled by '15/50' (or '3/10' or '0.3').   Reason: The count 15 represents the frequency (the actual number of times students chose football). The ratio of this frequency to the total sample size of 50 studenRead more

    The blank for the concept is filled by ‘relative frequency’.

    The blank for the value is filled by ’15/50′ (or ‘3/10’ or ‘0.3’).

     

    Reason: The count 15 represents the frequency (the actual number of times students chose football). The ratio of this frequency to the total sample size of 50 students defines the relative frequency:

    Relative frequency = 15 / 50 = 3 / 10 = 0.3 (or 30%).

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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    • 21
  4. (i) 0 (An event that cannot happen at all has a probability of 0). (ii) sample space (The collection containing every possible result of a trial is defined as the sample space). (iii) 1 (An event guaranteed to take place has maximum likelihood, which equals 1). (iv) 1/2 or 0.5 (A fair coin possessesRead more

    (i) 0 (An event that cannot happen at all has a probability of 0).

    (ii) sample space (The collection containing every possible result of a trial is defined as the sample space).

    (iii) 1 (An event guaranteed to take place has maximum likelihood, which equals 1).

    (iv) 1/2 or 0.5 (A fair coin possesses two symmetric, equally likely outcomes, heads and tails, giving P(heads) = 1/2).

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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    • 21
  5. Let the radius of the circle be r cm. Given circumference = 44 cm. The formula for the perimeter of a circle is: Circumference = 2 x π x r Substitute π = 22/7: 44 = 2 x (22/7) x r 44 = (44/7) x r Multiply both sides by 7 and divide by 44: r = (44 x 7) / 44 r = 7 cm. Therefore, the radius of the circRead more

    Let the radius of the circle be r cm.

    Given circumference = 44 cm.

    The formula for the perimeter of a circle is: Circumference = 2 x π x r

    Substitute π = 22/7: 44 = 2 x (22/7) x r 44 = (44/7) x r

    Multiply both sides by 7 and divide by 44: r = (44 x 7) / 44 r = 7 cm.

    Therefore, the radius of the circle is 7 cm.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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