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  1. Asked: In:

    Molecular mass of glucose is

    Mohan Batra

    (a) Molecular mass of glucose (C₆H₁₂O₆) = 6 x 12 + 12x1 + 6 x 16 = 72 + 12 + 96 = 180 u. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

    (a) Molecular mass of glucose (C₆H₁₂O₆) = 6 x 12 + 12×1 + 6 x 16 = 72 + 12 + 96 = 180 u.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

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  2. Asked: In:

    Tick the correct statement

    Mohan Batra

    (c) https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

    (c)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

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  3. Asked: In:

    Atoms of a given element are identical

    Mohan Batra

    (b) in mass and chemical properties. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

    (b) in mass and chemical properties.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

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  5. Asked: In:

    Magnesium and sulphur combine to form magnesium sulphide with the masses of magnesium and sulphur in the ratio of

    Mohan Batra

    (C) Mg + S → MgS 24 g 32 g Ratio by mass in which Mg and S combine = 24:32 or 3:4 https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

    (C) Mg + S → MgS
    24 g 32 g
    Ratio by mass in which Mg and S combine = 24:32 or 3:4

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

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  6. Asked: In:

    Which of the following are physical changes? (i) Melting of iron metal (ii) Rusting of iron (iii) Bending of an iron rod (iv) Drawing a wire of iron metal

    Mohan Batra

    (c) Changes (i), (iii) and (iv) are physical in nature because we can get back to the original form by physical methods. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/

    (c) Changes (i), (iii) and (iv) are physical in nature because we can get back to the original form by physical methods.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-2/

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