What's your question?
  1. Choice (a) is correct Given, ⁿP₃ : ⁿP₄ = 1 : 5  ⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n - 4)!) = 1/5 ⇒ (n - 4)!/ (n -3)! = 1/5 ⇒ (n - 4)! / (n - 3) (n - 4)! = 1/5 ⇒ 1 / n - 3 = 1/5 ⇒ n - 3 = 5 ⇒ n = 8  This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and CRead more

    Choice (a) is correct
    Given, ⁿP₃ : ⁿP₄ = 1 : 5 
    ⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n – 4)!) = 1/5 ⇒ (n – 4)!/ (n -3)! = 1/5
    ⇒ (n – 4)! / (n – 3) (n – 4)! = 1/5 ⇒ 1 / n – 3 = 1/5
    ⇒ n – 3 = 5 ⇒ n = 8 
    This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6

    See less
    • 7
  2. Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ,  then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈  n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more

    Choice (a) is correct.
    We know that if ⁿCᵣ = ⁿCₛ,  then r = s or r + s = n
    Given, ⁿC₁₂ = ⁿC₈ 
    n = 12 + 8 ⇒ n = 20
    This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6

    See less
    • 14
  3. Choice (b) is correct.  Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more

    Choice (b) is correct. 
    Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
    11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
    This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6

    See less
    • 5
  4. (c) Undefined nuclear region in prokaryotes is called nucleoid. Nucleoid is not bounded by nuclear envelope. Nucleous is absent. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/

    (c) Undefined nuclear region in prokaryotes is called nucleoid. Nucleoid is not bounded by nuclear envelope. Nucleous is absent.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/

    See less
    • 5
  5. (d) Contractile vacuole aids in osmoregulation as well as excretion. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/

    (d) Contractile vacuole aids in osmoregulation as well as excretion.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/

    See less
    • 17