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If ⁿP₃ = ⁿP₄ = 1 : 5, then the value of n is :
Choice (a) is correct Given, ⁿP₃ : ⁿP₄ = 1 : 5 ⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n - 4)!) = 1/5 ⇒ (n - 4)!/ (n -3)! = 1/5 ⇒ (n - 4)! / (n - 3) (n - 4)! = 1/5 ⇒ 1 / n - 3 = 1/5 ⇒ n - 3 = 5 ⇒ n = 8 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and CRead more
Choice (a) is correct
Given, ⁿP₃ : ⁿP₄ = 1 : 5
⇒ ⁿP₃/ ⁿP₄ = 1/5 ⇒ (n!/(n -3)!)/ (n!/ (n – 4)!) = 1/5 ⇒ (n – 4)!/ (n -3)! = 1/5
⇒ (n – 4)! / (n – 3) (n – 4)! = 1/5 ⇒ 1 / n – 3 = 1/5
⇒ n – 3 = 5 ⇒ n = 8
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ⁿC₁₂ = ⁿC₈, then the value of n is :
Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈ n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more
Choice (a) is correct.
We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n
Given, ⁿC₁₂ = ⁿC₈
n = 12 + 8 ⇒ n = 20
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
What is the value of n!/(n – r)! r! if n = 11 and r = 3?
Choice (b) is correct. Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more
Choice (b) is correct.
Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
The nuclear region of prokaryotes is also known as
(c) Undefined nuclear region in prokaryotes is called nucleoid. Nucleoid is not bounded by nuclear envelope. Nucleous is absent. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
(c) Undefined nuclear region in prokaryotes is called nucleoid. Nucleoid is not bounded by nuclear envelope. Nucleous is absent.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
See lessContractile vacuole takes part in
(d) Contractile vacuole aids in osmoregulation as well as excretion. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
(d) Contractile vacuole aids in osmoregulation as well as excretion.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-5/
See less