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The cost of a journey is given by the linear function C(d) = 100 + 60d, where C indicates total cost in rupees and d the distance travelled in km. Let us make a table of values for d varying from 0 to 10 km and show how the cost increases for every km.
The linear function C(d) = 100 + 60d represents the total journey cost, where d is the distance travelled in kilometres. The fixed charge is 100 rupees and the cost increases by 60 rupees for every kilometre. For example, when d equals 0, the cost is 100 rupees and when d equals 1, the cost becomesRead more
The linear function C(d) = 100 + 60d represents the total journey cost, where d is the distance travelled in kilometres. The fixed charge is 100 rupees and the cost increases by 60 rupees for every kilometre. For example, when d equals 0, the cost is 100 rupees and when d equals 1, the cost becomes 160 rupees. The pattern continues with a constant increase of 60 rupees each time. Therefore, this function represents linear growth because the increase remains fixed.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe height of water in a cylindrical tank is 3 m at the start of summer. The height h m at the end of t months is given by the linear function h(t) = 3 – 0.5t.
The height of water in the tank at the start of summer is 3 metres. According to the function h(t) = 3 minus 0.5t, the water level decreases by 0.5 metre every month. For example, after 1 month, the height becomes 2.5 metres and after 2 months, it becomes 2 metres. Since the height decreases by theRead more
The height of water in the tank at the start of summer is 3 metres. According to the function h(t) = 3 minus 0.5t, the water level decreases by 0.5 metre every month. For example, after 1 month, the height becomes 2.5 metres and after 2 months, it becomes 2 metres. Since the height decreases by the same amount every month, the pattern represents linear decay. The variable t shows the number of months, while h gives the water height.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessSuppose a plant has height 1.75 feet and it grows by 0.5 feet each month. (i) Find the height after 7 months. (ii) Make a table of values for t varying from 0 to 10 months and show how the height, h, increases every month. (iii) Find an expression that relates h and t and explain why it represents linear growth.
The plant is initially 1.75 feet tall and grows by 0.5 feet every month. After 7 months, its height becomes 1.75 plus 0.5 multiplied by 7, which equals 5.25 feet. A table from 0 to 10 months will show a regular increase of 0.5 feet each month. If t represents the number of months and h represents thRead more
The plant is initially 1.75 feet tall and grows by 0.5 feet every month. After 7 months, its height becomes 1.75 plus 0.5 multiplied by 7, which equals 5.25 feet. A table from 0 to 10 months will show a regular increase of 0.5 feet each month. If t represents the number of months and h represents the height, then the relation is h = 1.75 + 0.5t. This represents linear growth because the increase is constant every month.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA mobile phone is bought for rupees 10,000. Its value decreases by rupees 800 every year. (i) Find the value of the phone after 3 years. (ii) Make a table of values for t varying from 0 to 8 years and show how the value of the phone, v, depreciates with time. (iii) Find an expression that relates v and t and explain why it represents linear decay.
The mobile phone is bought for 10000 rupees and loses 800 rupees in value every year. After 3 years, the value decreases by 800 multiplied by 3, which equals 2400 rupees. Therefore, the remaining value becomes 10000 minus 2400, which equals 7600 rupees. If t represents the number of years and v reprRead more
The mobile phone is bought for 10000 rupees and loses 800 rupees in value every year. After 3 years, the value decreases by 800 multiplied by 3, which equals 2400 rupees. Therefore, the remaining value becomes 10000 minus 2400, which equals 7600 rupees. If t represents the number of years and v represents the value of the phone, then the expression is v = 10000 minus 800t. This represents linear decay because the decrease remains constant every year.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessNCERT Solutions for Class 9 Sanskrit Sharada Chapter 4 Question Answer
Chapter 4 “Na Khalu Vayastējaso Hetuḥ” explains that age is not the reason for greatness or strength. True greatness comes from knowledge, wisdom and good qualities. इस अध्याय में बताया गया है कि व्यक्ति की उम्र नहीं बल्कि उसका ज्ञान, बुद्धि और गुण उसे महान बनाते हैं। यह अध्याय विद्यार्थियों को आत्मRead more
Chapter 4 “Na Khalu Vayastējaso Hetuḥ” explains that age is not the reason for greatness or strength. True greatness comes from knowledge, wisdom and good qualities. इस अध्याय में बताया गया है कि व्यक्ति की उम्र नहीं बल्कि उसका ज्ञान, बुद्धि और गुण उसे महान बनाते हैं। यह अध्याय विद्यार्थियों को आत्मविश्वास, नैतिकता और सही सोच विकसित करने की प्रेरणा देता है तथा जीवन में योग्य बनने का संदेश देता है।
एनसीईआरटी समाधान कक्षा 9 की संस्कृत पाठ्यपुस्तक शारदा अध्याय 4 न खलु वयस्तेजसो हेतुः प्रश्न उत्तर
NCERT Solutions for Class 9 Sanskrit Sharada Chapter 4 Na Khalu Vayastējaso Hetuḥ Question Answer (2026-27):
https://hindi.tiwariacademy.com/ncert-solutions/class-9/sanskrit/sharada-chapter-4/
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