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  1. (c) A mutual sound has three characteristics namely (i) loudness, (ii) pitch and (iii) quality or timbre. Wavelength is not a characteristic of a musical sound. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

    (c) A mutual sound has three characteristics namely (i) loudness, (ii) pitch and (iii) quality or timbre. Wavelength is not a characteristic of a musical sound.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

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  2. (b) For sound waves (in general for all longitudinal waves) distance from centre of one compression (or rarefaction) to next centre of compression (or rarefaction) is equal to one wavelength λ. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

    (b) For sound waves (in general for all longitudinal waves) distance from centre of one compression (or rarefaction) to next centre of compression (or rarefaction) is equal to one wavelength λ.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

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  3. (d) Sound waves can travel in all media whether a solid or a liquid or a gas. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

    (d) Sound waves can travel in all media whether a solid or a liquid or a gas.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-11/

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  4. Triangular numbers are in the form that every number denotes the sum of dots that make up an equilateral triangle. The formula for the nth triangular number is given as: Tₙ = n(n + 1) /₂. For the following sequence: T₁ = 1, T₂ = 3, T₃ = 6, T₄ = 10. The following number in the sequence is T₅ = 5(5 +Read more

    Triangular numbers are in the form that every number denotes the sum of dots that make up an equilateral triangle. The formula for the nth triangular number is given as:
    Tₙ = n(n + 1) /₂.

    For the following sequence:
    T₁ = 1, T₂ = 3, T₃ = 6, T₄ = 10.
    The following number in the sequence is T₅ = 5(5 + 1) /₂ = 15.

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-1/

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  5. Square numbers are constructed by adding consecutive odd numbers. The trend for square numbers is determined as follows: 1 = 1² 1 + 3 = 4 = 2² 1 + 3 + 5 = 9 = 3² 1 + 3 + 5 + 7 = 16 = 4² This continues and yet the sum of the first n odd numbers always equates to n². Click here for more: https://www.tRead more

    Square numbers are constructed by adding consecutive odd numbers. The trend for square numbers is determined as follows:

    1 = 1²
    1 + 3 = 4 = 2²
    1 + 3 + 5 = 9 = 3²
    1 + 3 + 5 + 7 = 16 = 4²

    This continues and yet the sum of the first n odd numbers always equates to n².

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-1/

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