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  1. We are given that the angles A, B, and C of a triangle △ABC form an increasing arithmetic progression (AP). We need to find the value of sin B. Step 1: Properties of angles in a triangle The sum of the angles in any triangle is: A + B + C = 180°. Since A, B, and C form an increasing arithmetic progrRead more

    We are given that the angles A, B, and C of a triangle △ABC form an increasing arithmetic progression (AP). We need to find the value of sin B.

    Step 1: Properties of angles in a triangle
    The sum of the angles in any triangle is:
    A + B + C = 180°.

    Since A, B, and C form an increasing arithmetic progression, let the common difference of the AP be d. Then we can write:
    A = B – d, B = B, C = B + d.

    Substitute these into the angle sum property:
    (B – d) + B + (B + d) = 180°.

    Simplify:
    3B = 180°.

    Solve for B:
    B = 60°.

    Step 2: Find sin B
    Now that we know B = 60°, we use the standard trigonometric value:
    sin 60° = √3/2.

    Step 3: Final Answer
    The value of sin B is:
    √3/2.

    The correct answer is:
    b) √3/2
    This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/

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  2. To determine which of the given trigonometric expressions is not defined, we analyze each option based on the definitions and properties of trigonometric functions. Step 1: Analyze each option a) cos 0° The cosine function is defined for all real numbers. The value of cos 0° is: cos 0° = 1. Thus, coRead more

    To determine which of the given trigonometric expressions is not defined, we analyze each option based on the definitions and properties of trigonometric functions.

    Step 1: Analyze each option

    a) cos 0°
    The cosine function is defined for all real numbers. The value of cos 0° is:
    cos 0° = 1.
    Thus, cos 0° is defined.

    b) tan 45°
    The tangent function is defined as tan θ = sin θ / cos θ. For θ = 45°:
    tan 45° = sin 45° / cos 45° = (1/√2) / (1/√2) = 1.
    Thus, tan 45° is defined.

    c) sec 90°
    The secant function is defined as sec θ = 1 / cos θ. For θ = 90°:
    cos 90° = 0.
    Since division by zero is undefined, sec 90° = 1 / cos 90° = 1 / 0 is not defined.
    Thus, sec 90° is not defined.

    d) sin 90°
    The sine function is defined for all real numbers. The value of sin 90° is:
    sin 90° = 1.
    Thus, sin 90° is defined.

    Step 2: Final Answer
    The expression that is not defined is:
    c) sec 90°.
    This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/

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    • 14
  3. We are given: sinθ = x and secθ = y. Step 1: Recall the trigonometric identities 1. The definition of secθ is: secθ = 1/cosθ. Therefore, cosθ = 1/secθ = 1/y. 2. The definition of tanθ is: tanθ = sinθ / cosθ. Step 2: Substitute the values of sinθ and cosθ From the problem, sinθ = x and cosθ = 1/y. SuRead more

    We are given:
    sinθ = x and secθ = y.
    Step 1: Recall the trigonometric identities
    1. The definition of secθ is:
    secθ = 1/cosθ.
    Therefore, cosθ = 1/secθ = 1/y.

    2. The definition of tanθ is:
    tanθ = sinθ / cosθ.
    Step 2: Substitute the values of sinθ and cosθ
    From the problem, sinθ = x and cosθ = 1/y. Substituting these into the formula for tanθ:

    tanθ = sinθ / cosθ
    = x / (1/y)

    Step 3: Simplify the expression
    Dividing by 1/y is equivalent to multiplying by y:

    tanθ = x * y
    = xy

    Step 4: Final Answer
    Thus, tanθ is equal to xy.

    The correct answer is:
    a) xy
    This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/

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    • 25
  4. The potential difference (ΔV) in a uniform electric field is given by: ΔV = − E⋅d. where: E=100N/C (electric field strength) d = 5 cm = 0.05 m (displacement in the field direction) ΔV = −(100×0.05) ΔV = −5 V Since the question asks for the decrease in potential, the answer is: (c) 5 V For more visitRead more

    The potential difference (ΔV) in a uniform electric field is given by:

    ΔV = − E⋅d.
    where:
    E=100N/C (electric field strength)
    d = 5 cm = 0.05 m (displacement in the field direction)
    ΔV = −(100×0.05)
    ΔV = −5 V
    Since the question asks for the decrease in potential, the answer is: (c) 5 V

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/

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    • 15
  5. We are given the equation: 5 tanθ - 4 = 0. Step 1: Solve for tanθ Rearrange the equation to solve for tanθ: 5 tanθ = 4 tanθ = 4/5. Step 2: Express sinθ and cosθ in terms of tanθ Using the identity tanθ = sinθ / cosθ, we can write: sinθ = 4k and cosθ = 5k, where k is a positive constant such that sinRead more

    We are given the equation:
    5 tanθ – 4 = 0.

    Step 1: Solve for tanθ
    Rearrange the equation to solve for tanθ:
    5 tanθ = 4
    tanθ = 4/5.

    Step 2: Express sinθ and cosθ in terms of tanθ
    Using the identity tanθ = sinθ / cosθ, we can write:
    sinθ = 4k and cosθ = 5k,
    where k is a positive constant such that sin²θ + cos²θ = 1 (Pythagorean identity).

    Substitute sinθ = 4k and cosθ = 5k into the identity:
    (4k)² + (5k)² = 1
    16k² + 25k² = 1
    41k² = 1
    k² = 1/41
    k = √(1/41).

    Thus:
    sinθ = 4k = 4/√41,
    cosθ = 5k = 5/√41.

    Step 3: Simplify the given expression
    We are tasked with finding the value of:
    (5 sinθ – 4 cosθ) / (5 sinθ + 4 cosθ).

    Substitute sinθ = 4/√41 and cosθ = 5/√41 into the expression:

    Numerator:
    5 sinθ – 4 cosθ = 5(4/√41) – 4(5/√41)
    = (20/√41) – (20/√41)
    = 0.

    Denominator:
    5 sinθ + 4 cosθ = 5(4/√41) + 4(5/√41)
    = (20/√41) + (20/√41)
    = 40/√41.

    Thus, the entire expression becomes:
    (5 sinθ – 4 cosθ) / (5 sinθ + 4 cosθ) = 0 / (40/√41) = 0.

    Step 4: Final Answer
    The value of the given expression is 0.

    The correct answer is:
    c) zero
    This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/

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