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At a given distance from the centre of short electric dipole, field intensity on axial line is k times the field intensity on equatorial line, where k =
For a short electric dipole, the electric field intensity on the axial line is twice that on the equatorial line at the same distance. This follows from the standard dipole field equations: E_axial = (2kP) / r³ and E_equatorial = (kP) / r³, giving E_axial / E_equatorial = 2. Answer: (a) 2. For moreRead more
For a short electric dipole, the electric field intensity on the axial line is twice that on the equatorial line at the same distance. This follows from the standard dipole field equations:
E_axial = (2kP) / r³ and E_equatorial = (kP) / r³, giving E_axial / E_equatorial = 2.
Answer: (a) 2.
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When a plastic comb is passed through dry hair, the charge acquired by the comb is
When a plastic comb is passed through dry hair, it acquires a negative charge due to the transfer of electrons from the hair to the comb. Hair loses electrons and becomes positively charged, while the comb gains electrons and becomes negatively charged, following the principle of triboelectric chargRead more
When a plastic comb is passed through dry hair, it acquires a negative charge due to the transfer of electrons from the hair to the comb. Hair loses electrons and becomes positively charged, while the comb gains electrons and becomes negatively charged, following the principle of triboelectric charging.
Answer: (a) Always negative.
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Electric field due to an electric dipole is
The electric field due to an electric dipole is cylindrically symmetric around the axis joining the two charges. This symmetry arises because the field depends on the dipole moment and varies with position but remains symmetric about the dipole axis. Answer: (b) cylindrically symmetric. For more visRead more
The electric field due to an electric dipole is cylindrically symmetric around the axis joining the two charges. This symmetry arises because the field depends on the dipole moment and varies with position but remains symmetric about the dipole axis.
Answer: (b) cylindrically symmetric.
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0.6666 in p/q form is:
We are given the repeating decimal 0.6666... and need to express it in the form p/q. Step 1: Let x = 0.6666... Step 2: Multiply by 10 to shift the decimal point 10x = 6.666... Step 3: Subtract the two equations 10x - x = 6.6666... - 0.6666.. 9x = 6 Step 4: Solve for x x = 6/9 Step 5: Simplify theRead more
We are given the repeating decimal 0.6666… and need to express it in the form p/q.
Step 1: Let x = 0.6666…
Step 2: Multiply by 10 to shift the decimal point
10x = 6.666…
Step 3: Subtract the two equations
10x – x = 6.6666… – 0.6666..
9x = 6
Step 4: Solve for x
x = 6/9
Step 5: Simplify the fraction 6/9 = 2/3
Conclusion: The correct answer is 2/3 (option b).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
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Which one of the following is a rational number:
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0. Now, let's check each option: (a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers. (b). √2 The square root of 2 is also irrational because it has a nRead more
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0.
Now, let’s check each option:
(a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers.
(b). √2 The square root of 2 is also irrational because it has a non-repeating , non-terminating decimal expansion.
(c). 0 Zero can be written as 0/1, which is in the form p/q where p = 0 and q = 1. Since it satisfies the definition of a rational number, 0 is rational.
(d). √5 The square root of 5 is irrational for the same reasons as √2 and √3.
Conclusion: The only rational number in the given option is 0 (option c).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/