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How can one present a project on Jogati Manjamma with pictures and descriptions?
To present a project on Jogati Manjamma, include sections covering her early life, struggles, dance contributions and national recognition. Use pictures of her performances, awards and events to visually highlight her journey. Describe her role in preserving Jogati Dance and breaking gender barriersRead more
To present a project on Jogati Manjamma, include sections covering her early life, struggles, dance contributions and national recognition. Use pictures of her performances, awards and events to visually highlight her journey. Describe her role in preserving Jogati Dance and breaking gender barriers. Discuss her impact on folk arts and the significance of her recognition, like the Padma Shri. Adding quotes or video links can enhance the project, making it more informative and engaging.
See lessA long solenoid carrying current produces a magnetic field B along its axis. If the number of turns in the solenoid is halved and current in it is doubled the new magnetic field will be :
The correct answer is (B) B. The magnetic field inside a long solenoid is given by: B = μonI Where n = number of turns per unit length and I = current. If the number of turns is halved (n/2) and current is doubled (2I), the new magnetic field becomes: B' = μ0 n/2 2I = μ0 nI = B Answer: (B) B. httRead more
The correct answer is (B) B.
The magnetic field inside a long solenoid is given by:
B = μonI
Where n = number of turns per unit length and
I = current.
If the number of turns is halved (n/2) and current is doubled (2I), the new magnetic field becomes:
B’ = μ0
n/2 2I = μ0
nI = B
Answer: (B) B.
https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/
See lessThe current sensitivity of a moving coil galvanometer increases by 35%, when its resistance is increased by a factor 3. The voltage sensitivity of galvanometer changes by a factor
The current sensitivity of a moving coil galvanometer is given by: Si = N AB/K Where: N = Number of turns A = Area of coil B = Magnetic field K= Torsional constant When the resistance (R) of the galvanometer increases by a factor of 3, the voltage sensitivity (Sv) is given by: Sv = Si/R Since currenRead more
The current sensitivity of a moving coil galvanometer is given by:
Si = N AB/K
Where:
N = Number of turns
A = Area of coil
B = Magnetic field
K= Torsional constant
When the resistance (R) of the galvanometer increases by a factor of 3, the voltage sensitivity (Sv) is given by:
Sv = Si/R
Since current sensitivity increases by 35%, we have:
Sv′ = 1.35 × Si/3R = 1.35/3 × Sv = 0.45 × Sv
Hence, the voltage sensitivity decreases by 55% (100%−45%
Answer: (C) 55%
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/
A galvannometer having a resistance of 20 Ω and 30 divisions on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt is
The voltage range of a voltmeter is given by: V = (n × k) × (RG + R) Where: n = 30 divisions k = 0.005 A/division (figure of merit) Rg = 20 Ω (galvanometer resistance) V = 15 volts 15 = (30 × 0.005) × (20 + R) 15 = 0.15 × (20 + R) 20 + R = 15/0.15 = 100 R = 80Ω Answer: (C) 80 Ω For more visit here:Read more
The voltage range of a voltmeter is given by:
V = (n × k) × (RG + R)
Where:
n = 30 divisions
k = 0.005 A/division (figure of merit)
Rg = 20 Ω (galvanometer resistance)
V = 15 volts
15 = (30 × 0.005) × (20 + R)
15 = 0.15 × (20 + R)
20 + R = 15/0.15 = 100
R = 80Ω
Answer: (C) 80 Ω
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/
A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E and B represents the electric fields and magnetic fields respectively, then this region of space may have:
A proton moving with constant velocity implies no net force acts on it. The force on a proton due to electric and magnetic fields is given by: F =q( E + v × B) For no change in velocity, 0F =0, which is possible if: E =0 and B =0 E =0, B ≠0 (if velocity is parallel to magnetic field) Answer: (A) E =Read more
A proton moving with constant velocity implies no net force acts on it. The force on a proton due to electric and magnetic fields is given by:
F =q( E + v × B)
For no change in velocity,
0F =0, which is possible if:
E =0 and B =0
E =0, B ≠0
(if velocity is parallel to magnetic field)
Answer: (A) E = 0, B = 0
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/