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Why do clothes dry faster on a windy day?
The correct answer is (B) Wind increases evaporation rate. On a windy day, the moving air carries away water vapor from the surface of clothes, speeding up the evaporation process. This helps clothes dry faster compared to a still, humid environment where moisture remains in the air. For more visitRead more
The correct answer is (B) Wind increases evaporation rate.
On a windy day, the moving air carries away water vapor from the surface of clothes, speeding up the evaporation process. This helps clothes dry faster compared to a still, humid environment where moisture remains in the air.
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The water droplets seen on a cold glass of water in summer are due to:
The correct answer is (D) Condensation. In summer, warm air contains moisture in the form of water vapor. When this humid air comes into contact with the cold surface of the glass, it cools down, causing the water vapor to condense into tiny droplets of liquid water. For more visit here: https://wwwRead more
The correct answer is (D) Condensation.
In summer, warm air contains moisture in the form of water vapor. When this humid air comes into contact with the cold surface of the glass, it cools down, causing the water vapor to condense into tiny droplets of liquid water.
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The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54, 84 is
Arrange the data in ascending order: 22, 34, 39, 45, 54, 54, 56, 68, 78, 84. Count the number of observations. There are 10 numbers (even count). Find the median. For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbeRead more
Arrange the data in ascending order:
22, 34, 39, 45, 54, 54, 56, 68, 78, 84.
Count the number of observations.
There are 10 numbers (even count).
Find the median.
For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbers:
5th number = 54,
6th number = 54.
Median = (54 + 54) / 2 = 54.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
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The mean of 5 numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is
We are given the following information: - The mean of 5 numbers is 30. - When one number is excluded, the mean of the remaining 4 numbers becomes 28. Calculate the total sum of the 5 numbers. The formula for the mean is: Mean = (Sum of all observations) / (Number of observations). For the 5 numbers:Read more
We are given the following information:
– The mean of 5 numbers is 30.
– When one number is excluded, the mean of the remaining 4 numbers becomes 28.
Calculate the total sum of the 5 numbers.
The formula for the mean is:
Mean = (Sum of all observations) / (Number of observations).
For the 5 numbers:
Mean = 30,
Number of observations = 5.
Substitute into the formula:
30 = (Sum of all 5 numbers) / 5.
Multiply through by 5:
Sum of all 5 numbers = 30 × 5 = 150.
Calculate the total sum of the remaining 4 numbers.
When one number is excluded, the mean of the remaining 4 numbers is 28. Using the same formula:
Mean = (Sum of remaining 4 numbers) / (Number of observations).
For the 4 numbers:
Mean = 28,
Number of observations = 4.
Substitute into the formula:
28 = (Sum of remaining 4 numbers) / 4.
Multiply through by 4:
Sum of remaining 4 numbers = 28 × 4 = 112.
Find the excluded number.
The excluded number is the difference between the total sum of the 5 numbers and the sum of the remaining 4 numbers:
Excluded number = (Sum of all 5 numbers) – (Sum of remaining 4 numbers).
Substitute the values:
Excluded number = 150 – 112 = 38.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
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The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class limit of the lowest class is 10. The upper class limit of the highest class is:
Ans. Correct Option a) 35 We are given the following information: - The width of each class in the frequency distribution is 5. - The lower class limit of the lowest class is 10. - There are 5 continuous classes. Determine the class intervals. Each class has a width of 5, so the class intervals canRead more
Ans. Correct Option a) 35
We are given the following information:
– The width of each class in the frequency distribution is 5.
– The lower class limit of the lowest class is 10.
– There are 5 continuous classes.
Determine the class intervals.
Each class has a width of 5, so the class intervals can be written as:
1. First class: 10 – 15 (lower limit = 10, upper limit = 10 + 5 = 15),
2. Second class: 15 – 20,
3. Third class: 20 – 25,
4. Fourth class: 25 – 30,
5. Fifth class: 30 – 35.
Identify the upper class limit of the highest class.
From the above intervals, the highest class is the fifth class, which has an upper class limit of 35.
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