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  1. Schools can promote musical learning by introducing regular music classes, providing access to instruments and hiring trained instructors. Organizing music competitions, talent shows and workshops with professional musicians can inspire students. Forming school bands and orchestras allows students tRead more

    Schools can promote musical learning by introducing regular music classes, providing access to instruments and hiring trained instructors. Organizing music competitions, talent shows and workshops with professional musicians can inspire students. Forming school bands and orchestras allows students to perform, boosting confidence. Music should be integrated into the curriculum to emphasize its importance. Financial assistance or scholarships for instrument learning can further encourage participation, making music education more accessible and appealing to students.

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  2. Local musicians play a crucial role in preserving and promoting traditional music. They teach students, conduct workshops and perform at cultural events, keeping musical traditions alive. By incorporating folk and classical elements in modern compositions, they make traditional music relevant to youRead more

    Local musicians play a crucial role in preserving and promoting traditional music. They teach students, conduct workshops and perform at cultural events, keeping musical traditions alive. By incorporating folk and classical elements in modern compositions, they make traditional music relevant to younger audiences. Local artists also document, archive and innovate traditional styles, ensuring they remain significant. Their efforts help sustain indigenous musical heritage and pass down rich cultural traditions to future generations.

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  3. In a potentiometer experiment, the internal resistance of the cell can be determined using the formula: L₁/L₂ = r + R/r where L₁ is the original balancing length, L₂ is the new balancing length, r is the internal resistance, and R is the external resistance. Substituting the values, we get r = 3Ω. TRead more

    In a potentiometer experiment, the internal resistance of the cell can be determined using the formula:
    L₁/L₂ = r + R/r
    where
    L₁ is the original balancing length, L₂ is the new balancing length,
    r is the internal resistance, and R is the external resistance. Substituting the values, we get
    r = 3Ω. Therefore, the internal resistance is 3 Ω. The correct answer is (c) 3 Ω.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

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  4. The total resistance in the circuit is Rcell+Rwire = 3Ω + 3Ω = 6Ω The current is I = 10V/6Ω = 5/3 A. The potential gradient is V/L = IR/500 = 5/3 3/500 = 10 mV/cm. Answer: (b). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    The total resistance in the circuit is Rcell+Rwire = 3Ω + 3Ω = 6Ω
    The current is I = 10V/6Ω = 5/3 A. The potential gradient is V/L = IR/500 = 5/3 3/500 = 10 mV/cm. Answer: (b).

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

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  5. Let P₁ and P₂ be powers across R₁ and R₂. In series, power is divided inversely as resistance. In parallel, power is directly proportional to conductance. Using given conditions and solving equations, the ratio P₁ /P₂ = 4. Answer: (b) 4. For more visit here: https://www.tiwariacademy.com/ncert-solutRead more

    Let P₁ and P₂ be powers across R₁ and R₂. In series, power is divided inversely as resistance. In parallel, power is directly proportional to conductance. Using given conditions and solving equations, the ratio P₁ /P₂ = 4. Answer: (b) 4.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

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