What's your question?
  1. In a potentiometer experiment, the internal resistance of the cell can be determined using the formula: L₁/L₂ = r + R/r where L₁ is the original balancing length, L₂ is the new balancing length, r is the internal resistance, and R is the external resistance. Substituting the values, we get r = 3Ω. TRead more

    In a potentiometer experiment, the internal resistance of the cell can be determined using the formula:
    L₁/L₂ = r + R/r
    where
    L₁ is the original balancing length, L₂ is the new balancing length,
    r is the internal resistance, and R is the external resistance. Substituting the values, we get
    r = 3Ω. Therefore, the internal resistance is 3 Ω. The correct answer is (c) 3 Ω.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    See less
    • 36
  2. The total resistance in the circuit is Rcell+Rwire = 3Ω + 3Ω = 6Ω The current is I = 10V/6Ω = 5/3 A. The potential gradient is V/L = IR/500 = 5/3 3/500 = 10 mV/cm. Answer: (b). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    The total resistance in the circuit is Rcell+Rwire = 3Ω + 3Ω = 6Ω
    The current is I = 10V/6Ω = 5/3 A. The potential gradient is V/L = IR/500 = 5/3 3/500 = 10 mV/cm. Answer: (b).

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    See less
    • 38
  3. Let P₁ and P₂ be powers across R₁ and R₂. In series, power is divided inversely as resistance. In parallel, power is directly proportional to conductance. Using given conditions and solving equations, the ratio P₁ /P₂ = 4. Answer: (b) 4. For more visit here: https://www.tiwariacademy.com/ncert-solutRead more

    Let P₁ and P₂ be powers across R₁ and R₂. In series, power is divided inversely as resistance. In parallel, power is directly proportional to conductance. Using given conditions and solving equations, the ratio P₁ /P₂ = 4. Answer: (b) 4.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    See less
    • 35
  4. Heat produced is given by Q = P × t. Gives P = 100W and t = 2minutes = 120s, we get: Q = 100 × 120 = 12000J = 12.0KJ Answer: (c) 12.0 kJ. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    Heat produced is given by Q = P × t. Gives P = 100W and t = 2minutes = 120s, we get:
    Q = 100 × 120 = 12000J = 12.0KJ
    Answer: (c) 12.0 kJ.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

    See less
    • 34
  5. Musical instruments are crafted using various materials, each influencing the instrument's tone. Wood is commonly used in guitars and violins due to its resonant properties. Metal is used in trumpets and cymbals for bright, sharp sounds. Clay is used in instruments like the ghatam, providing a deepRead more

    Musical instruments are crafted using various materials, each influencing the instrument’s tone. Wood is commonly used in guitars and violins due to its resonant properties. Metal is used in trumpets and cymbals for bright, sharp sounds. Clay is used in instruments like the ghatam, providing a deep percussive tone. Natural materials like gourds are used in instruments such as the sitar, which enhances resonance. The material plays a crucial role in shaping the instrument’s sound characteristics.

    See less
    • 28