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If an ammeter is to be used in place of voltmeter, then we must connect with the ammeter a :
An ammeter has low internal resistance and is designed to measure current by connecting in series with the circuit. To use it as a voltmeter, a high resistance must be connected in series to limit current and measure potential difference. This combination ensures minimal current through the meter whRead more
An ammeter has low internal resistance and is designed to measure current by connecting in series with the circuit. To use it as a voltmeter, a high resistance must be connected in series to limit current and measure potential difference. This combination ensures minimal current through the meter while allowing voltage measurement.
See lessAnswer: (D) high resistance in series.
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A current carrying wire kept in a uniform magnetic field will experience a maximum force when it is
The force on a current-carrying wire in a magnetic field is given by: F = BILsinθ The force is maximum when sinθ = 1, i.e., = 90° . This means the wire must be perpendicular to the magnetic field to experience the maximum force. Answer: (A) perpendicular to the magnetic field. For more visit here: hRead more
The force on a current-carrying wire in a magnetic field is given by:
F = BILsinθ
The force is maximum when sinθ = 1, i.e., = 90°
. This means the wire must be perpendicular to the magnetic field to experience the maximum force.
Answer: (A) perpendicular to the magnetic field.
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A straight conducting rod of length l and mass is suspended in a horizontal plane by a pair of flexible strings in a magnetic field of magnitude B. To remove the tension in the supporting strings, the magnitude of current in the wire is :
To remove tension in the strings, the magnetic force must balance the gravitational force: Bil = mg Rearranging for current I: I = mg/BL Thus, the magnitude of current needed to make the net force zero is: I = mg/BL Answer: (C) mg/IB For more visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
To remove tension in the strings, the magnetic force must balance the gravitational force:
Bil = mg
Rearranging for current I:
I = mg/BL
Thus, the magnitude of current needed to make the net force zero is:
I = mg/BL
Answer: (C) mg/IB
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The current sensitivity of a galvanometer increases by 20%. If its resistance also increases by 25%, the voltage sensitivity will
The voltage sensitivity of a galvanometer is given by: Voltage Sensitivity = Current Sensitivity/R If current sensitivity increases by 20% and resistance increases by 25%, the net change in voltage sensitivity is: 1.2/1.25 = 0.96 This indicates a 4% decrease in voltage sensitivity. Answer: (D) DecreRead more
The voltage sensitivity of a galvanometer is given by:
Voltage Sensitivity = Current Sensitivity/R
If current sensitivity increases by 20% and resistance increases by 25%, the net change in voltage sensitivity is:
1.2/1.25 = 0.96
This indicates a 4% decrease in voltage sensitivity.
Answer: (D) Decrease by 4%.
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A current of 5 A is flowing from east to west In a long straight wire kept on a horizontal table. The magnetic field developed at a distance of 10 cm due south on the table is :
The magnetic field around a long, straight current-carrying wire is given by: B = μ0I/2πr Substituting values: B = 4π × 10⁻⁷ × 5/2π × 0.10 = 1 × 10⁻⁵ T Using the right-hand thumb rule, the magnetic field at a point due south acts upward. Therefore, the correct answer is: (B) 1 × 10⁻⁵ T acting upwarRead more
The magnetic field around a long, straight current-carrying wire is given by:
B = μ0I/2πr
Substituting values:
B = 4π × 10⁻⁷ × 5/2π × 0.10 = 1 × 10⁻⁵ T
Using the right-hand thumb rule, the magnetic field at a point due south acts upward. Therefore, the correct answer is:
(B) 1 × 10⁻⁵ T acting upwards.
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