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Umangi Grover
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Asked: 2020-10-20T11:55:27+00:00 In:

A battery of 9 V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm , 0.5 ohm and 12 ohm, respectively. How much current would flow through the 12 ohm resistor?

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NCERT Solution for Class 10 Science Chapter 12
Electricity
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-221
Questions No-9

2020-2021cbsechapter 12class10electricityncertscience
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    2 Answers

    1. Total resistance, R = 0.2 โ„ฆ + 0.3 โ„ฆ + 0.4 โ„ฆ + 0.5 โ„ฆ + 12 โ„ฆ โ€“ 13.4 โ„ฆ
      Potential difference, V = 9 V
      Current through the series circuit, I =ย V/Rย =ย 12V/13.4ฮฉย = 0.67 A
      โˆต There is no division of current in series. Therefore current through 12 โ„ฆ resistor = 0.67 A.

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    2. Total resistance of resistors when connected in series is given by ๐‘…=๐‘…1+๐‘…2+๐‘…3+๐‘…4+๐‘…5 โŸน๐‘…=0.2 ฮฉ+0.3 ฮฉ+0.4 ฮฉ+0.5 ฮฉ+12 ฮฉ=13.4 ฮฉ
      According to Ohmโ€™s law, V = IR
      โŸน๐ผ=๐‘‰/๐‘…=9/13.4=0.67 ๐ด

      For more answers visit to website:
      https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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