NCERT Solutions for Class 7 Mathematics Chapter 6
Important NCERT Questions
Class vii Math Chapter 6 The Triangles and Its Properties Exercise 6.5
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 3
A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a Find the distance of the foot of the ladder from the wall
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Let AC be the ladder and A be the window.
Given: AC = 15 m, AB = 12 m, CB = a m
In right angled triangle ACB,
(Hypotenuse)² = (Base)² + (Perpendicular)² [By Pythagoras theorem]
⇒ (AC)² = (CB)² + (AB)²
⇒ (15)² = (a)² + (12)²
⇒ 225 = a² + 144
⇒ a² = 225 – 144 = 81
⇒ a √81 = 9 cm
Thus, the distance of the foot of the ladder from the wall is 9 m.
Class 7 Maths Chapter 6 Exercise 6.5
for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-6/