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(i) Express 49 as the sum of 7 odd numbers. (ii) Express 121 as the sum of 11 odd numbers.

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NCERT Solutions for Class 8 Mathematics Chapter 6
Important NCERT Questions
Square and Square Roots Chapter 6 Exercise 6.1
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 8

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1 Answer

  1. (i) 49 is the square of 7. Therefore it is the sum of 7 odd numbers.
    49 = 1 + 3 + 5 + 7 + 9 + 11 + 13
    (ii) 121 is the square of 11. Therefore it is the sum of 11 odd numbers
    121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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