Class 12 Physics
CBSE and UP Board
Electromagnetic Induction
Chapter-6 Exercise 6.9
NCERT Solutions for Class 12 Physics Chapter 6 Question 9
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Mutual inductance of a pair of coils, μ = 1.5 H
Initial current, I₁= 0 A Final current I₂ = 20 A
Change in current, dl = I2 — I₁= 20 — 0 = 20 A
Time taken for the change, t = 0.5 s
Induced emf e = dφ/dt ——————Eq-1
Where, dφ is the change in the flux linkage with the coil.
Emf is related with mutual inductance as:
e = μ dI /dt —————————-Eq-2
Equating equations (1) and (2), we get
dφ/dt = μ dI /dt
dφ = 1.5x(20)
= 30 Wb
Hence, the change in the flux linkage is 30 Wb.