Class 12 Physics
CBSE and UP Board
Moving Charges and Magnetism
Chapter-4 Exercise 4.14
Additional Exercise
NCERT Solutions Class 12 Physics Chapter 4 Question 14
Two concentric circular coils X and Y of radii 16 cm and 10 cm, respectively, lie in the same vertical plane containing the north to south direction. Coil X has 20 turns and carries a current of 16 A; coil Y has 25 turns and carries a current of 18 A. The sense of the current in X is anticlockwise, and clockwise in Y, for an observer looking at the coils facing west. Give the magnitude and direction of the net magnetic field due to the coils at their centre.
Share
Radius of coil X, r₁= 16 cm = 0.16 m
Radius of coil Y, r₂ = 10 cm = 0.1 m
Number of turns of on coil X, n₁ =20
Number of turns of on coil Y, n₂ = 25
Current in coil X, I₁= 16 A
Current in coil Y, I₂= 18 A
Magnetic field due to coil X at their centre is given by the relation,
B₁ = μ0 N₁l₁/2 r₁
Where,μ0 = permeability of free space = 4 π x 10⁻⁴ T m A⁻¹
B₁ = (4 π x 10⁻⁴ x 25 x 18 )/( 2 x 0.10) = 9 π x 10⁻⁴ T (Towards West)
Hence ,net magnetic field can be obtained as ,
B = B₂ -B₁ = 9 π x 10⁻⁴ T – 4 π x 10⁻⁴ T =5 π x 10⁻⁴T
= 5 x 3.14 x 10⁻⁴ T = 1.57 x 10 ⁻³ T (Towards West)