NCERT Solutions for Class 11 Science Kinematic 2
Important Board Questions
Kinematic
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Numericals Marks Questions
The displacement x of a particle varies with time as x = 4t² – 15t + 25. Find the position, velocity and acceleration of the particle at t = 0.
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position, x = 25 m
velocity = dx/dt = 8t-15,
t = 0, v = 0 – 15 = – 15 m/s
acceleration, a = dv/dt = 8 ms⁻²