Using area = (1/2) x base x height = 60 with base 10 cm gives height h = 12 cm. In the half-triangle right triangle with legs 5 cm and 12 cm, hypotenuse is √(5² + 12²) = 13 cm.
An isosceles triangle has base 10 cm and its area is 60 cm². What are the lengths of the equal sides?
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Given base b = 10 cm and Area = 60 cm².
Area = (1/2) x base x height
60 = (1/2) x 10 x h
60 = 5h, which gives height h = 12 cm.
The altitude to the base of an isosceles triangle bisects the base into two segments of length 10 / 2 = 5 cm.
By Pythagoras theorem, each equal side acts as the hypotenuse:
side² = 5² + 12² = 25 + 144 = 169
side = √169 = 13 cm.
Therefore, the lengths of the equal sides are 13 cm each.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/