We take out the common factor 1/5 from the entire expression. The remaining polynomial inside is 9s square + 30sv + 25v square, which condenses smoothly into (3s + 5v) square.
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We simplify this factorization by removing 1/5 as a common factor first. This leaves us with 1/5 multiplied by the expression 9s square + 30sv + 25v square. Now we can easily see that 9s square is the square of 3s, and 25v square is the square of 5v. The middle term matches two times 3s times 5v. The fully factored final form is 1/5 times (3s + 5v) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/