Let the number of five-rupee coins be x. Then the number of two-rupee coins is 3x. Their total value is 88 rupees. Solving the equation gives x equal to 8. Therefore, Ruby has 24 two-rupee coins and 8 five-rupee coins.
Ruby has 3 times as many two-rupee coins as she has five rupee-coins. If she has a total rupees 88, how many coins does she have of each type?
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Suppose Ruby has x five-rupee coins. Since she has three times as many two-rupee coins, the number of two-rupee coins becomes 3x. The total value of five-rupee coins is 5x rupees and the total value of two-rupee coins is 2 multiplied by 3x, which equals 6x rupees. Therefore, the total amount is 5x plus 6x equals 88. Solving gives 11x equals 88, so x equals 8. Hence, Ruby has 8 five-rupee coins and 24 two-rupee coins.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/